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(#M40016582) MBA question number systems, progressions Keep an EYE

the sum of the squares of the fifth and eleventh term of an AP is 3 and the product of the second and fourteenth term is equal to P. find the product of first and fifteenth term of the AP. plz tag me in the answer.

1) (58P-39)/45
2) (98P+39)/72
3) (116P-39)/90
4) (98P+39)/90

Asked In MBA (12 years ago)

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Dr.Dipin Singh  (12 years ago)

Already solved in m4maths

(T5)^2+(T11)^2=3

T2*T14=P

T1*T15=?

(a+4d)^2+(a+10d)^2=3
2a^2+28ad+116d^2=3.....(1)

(a+d)(a+13d)=P

a^2+14ad+13d^2=P

a^2+14ad = P- 13d^2

1.5-45d^2=P

2P=3-90d^2...........(2)

a^2+14ad=?

=P-13d^2

=P-13(3-2P)/90

=(116P-39)/90

option (C)

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