Latest TCS Aptitude Question SOLUTION: Reshma wrote 5papers for her board exams English Telugu maths science and social ..the max marks for each paper was 100. she got an aggregate of 63%. she applied for revaluation of

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Reshma wrote 5papers for her board exams English Telugu maths science and social ..the max marks for each paper was 100. she got an aggregate of 63%. she applied for revaluation of all papers. on revaluation English and Telugu marks were unchanged. she got 12marks more in maths. 2 marks less in social and 7 marks more in science. what is her new aggregate percentage???

Asked In TCS Omkar Joshi (5 years ago)

Unsolved Read Solution (8)

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Ajithkumar  (5 years ago)

Sol:

63% of 5 subjects=63×5=315
Revaluation changed mark=12-2+7=17
New total =315+17=332
New aggregate percentage=332/500=66.4%

Is this solution Helpfull? Yes (15) | No   

ishan dua  (4 years ago)

Total increment = 12 - 2 + 7 = 17
Total number of subjects = 5
increment in % = 17/5 = 3.4%
new percentage = 63 + 3.4 = 66.4%

Is this solution Helpfull? Yes (3) | No (1)  

shiyam  (4 years ago)

Sol:
aggregate mark=63% of 5 subjects.
63*5=315.
changes of marks is 12-2+7=17.
315+17=332.
now percetage is (total 5 subjects so new value /500) = 332/500 = 66.4%.


Hence Answer is 66.4% aggregated.

Is this solution Helpfull? Yes (2) | No   

ganesh babu  (4 years ago)

+12-2+7=+17
17/500*100=3.4
New percentage =63+3.4=66.4%

Is this solution Helpfull? Yes (1) | No   

Ankit singh  (5 years ago)

Marks before reevaluation 63×5=315

After reevaluation 315+12-2+7=332

332=x×500/100

x=332/5=66.4

Is this solution Helpfull? Yes | No (1)  

xyz  (5 years ago)

suppose five subject are x1,x2,x3,x4,x5
the (x1+x2+x3+x4+x5)/5=66

so when x3 is math and increase mars by 12 the new value of x2 is =x2+12
similare new x4=x4-2
and new x5=x5+7

then (x1+x2+(x3+12)+(x4-2)+(x5+7))/5=y
(x1+x2+x3+x4+x5)/5+(12-2+7)/5=y

63+(17)/5=y
63+3.4=y
y=66.4

Is this solution Helpfull? Yes | No (2)  

Swati Singh  (4 years ago)

clearly the marks changed are in only three subjects .The total change in the marks is (12-2+7)=17 marks .the initial marks of girl is x*100/500 = 63 ->x=63*5=315.now the changed marks is 315+17 which is 3332 .then percentage will be 315 *100 /5 = 66.4%

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bhavana  (4 years ago)

avg=sum of all sub/5
63=x/5
x=315
on revaluation she got 12+7-2 is 17
and 17 marks added to 315
then it is 332,avg=332/5=66.4

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