Latest MBA Aptitude Question SOLUTION: ABCD is a trapezium with AB parallel to CD. AC is perpendicular to BC and BD is perpendicular to AD. If AD=BC=15cm and AB=25cm , find the area of the trapezium ABCD.

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(#M40016683) MBA question mensuration, geometry & co-ordinate geometry Keep an EYE

ABCD is a trapezium with AB parallel to CD. AC is perpendicular to BC and BD is perpendicular to AD. If AD=BC=15cm and AB=25cm , find the area of the trapezium ABCD.

1) 192 cm^2
2) 232 cm^2
3) 172 cm^2
4) None of these
5) Cannot be Determined

Asked In MBA (11 years ago)

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Read Solution (1) :

Ravi Kumar  (7 years ago)

The Answer will be 192 cm^2

we can find out the area of triangle ADB
so height for this triangle wud be equal to the height of trapezium.

so we get height = 12cm.
now we can easily get to CD=7cm

and we know area of trapezium =1/2*(AB+CD)*HEIGHT

NOW,1/2*(25+7)*12 = 192 cm.

how to get CD=7 cm

when we will drop two perpendicular lines from D to AB as point E and from C to AB as point F.

So,we can see that EF = CD (as the line drawns were perpendicular)

Now In triangleADE,
We know AD=15 and DE=12
So we can easily find AE = 9

Similarly from triangleBCF,
we will get BF = 9cm

therefore,EF = AB -(AE+BF) = 25 - 18 =7cm.

Hope it Helps.:)

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