There are two Arithmetic Progressions A and B such that their nth terms are given by An 101 3 n

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Previous Question: there are two pockets, each containing 3 coins of diff denominations which are in AP and total value of coins in each pocket is Rs 21. the common diff of the first set of coins is greater than that of second set by 1,and the product of the first set is the product of the second set as 8 to 9. find the value of the coin of largest denominations,among six coins??

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(#M40016877) MBA question number systems, progressions Keep an EYE

There are two Arithmetic Progressions A and B such that their nth terms are given by An = 101 + 3(n – 1) andBn = 150 + (n – 1), where n is the set of natural numbers. The first 50 terms of A and B are written alternately i.e. A1B1A2B2…..A50B50. What is the remainder when the number so formed is divided by 11?

1) 0
2) 1
3) 9
4) 10: Asked In MBA (11 years ago); Unsolved; Is this Puzzle helpful? (0) (1) Submit Your Solution

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Latest MBA Aptitude Question SOLUTION: There are two Arithmetic Progressions A and B such that their nth terms are given by An = 101 + 3(n – 1) andBn = 150 + (n – 1), where n is the set of natural numbers. The first

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Latest MBA Aptitude Question SOLUTION: There are two Arithmetic Progressions A and B such that their nth terms are given by An = 101 + 3(n – 1) andBn = 150 + (n – 1), where n is the set of natural numbers. The first

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(#M40016877) MBA question number systems, progressions Keep an EYE

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