Latest MBA Aptitude Question SOLUTION: Seven different objects must be divided among three people. In how many ways can this be done if one or two of them must get no objects?

1) 381
2) 36
3) 84

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Previous Question: Find the least value of mode{x-1}+mode{x-2}+mode{x-3}+...........+mode{x-99}

1) 0
2) 50
3) 1225
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Next Question: If a2 = by + cz, b2 = cz + ax and c2 = ax + by, then is equal to

1) 1
2) 8
3) abc/xyz
4) x/a + y/b + z/c
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Seven different objects must be divided among three people. In how many ways can this be done if one or two of them must get no objects?

1) 381
2) 36
3) 84
4) 174
5) 180

Asked In MBA (11 years ago)

Unsolved Read Solution (2)

Is this Puzzle helpful?   (4)   (1) Submit Your Solution

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Read Solution (2) :

Vivek Jain  (10 years ago)

1)381
For the case when two of them must get no objects, ways = 3 (for 3 persons)
Then, for the case when one of them must get no objects = 3*2^7 - the overlapping case where two of them must get no objects
=3*2^7 - 3 =381

Is this solution Helpfull? Yes (3) | No (1)  

karthik  (11 years ago)

In 3^7 = 2187 ways, because each object can go to 3 different people, and by the rule of multiplying we get 3*3*...*3 = 3^7 ways.

Is this solution Helpfull? Yes | No (2)  

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Previous Question: Find the least value of mode{x-1}+mode{x-2}+mode{x-3}+...........+mode{x-99}

1) 0
2) 50
3) 1225
4) 2450
Next Question: If a2 = by + cz, b2 = cz + ax and c2 = ax + by, then is equal to

1) 1
2) 8
3) abc/xyz
4) x/a + y/b + z/c
5) 0

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