Latest MBA Aptitude Question SOLUTION: 90 is divided into 3 parts such that the sum of first 2 parts exceeds the sum of the second and third part by 18.if the smallest part is 18,then the greatest part is?pl. provide so

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(#M40016988) MBA question algebra, quadratic equations, inequalities, functions Keep an EYE

90 is divided into 3 parts such that the sum of first 2 parts exceeds the sum of the second and third part by 18.if the smallest part is 18,then the greatest part is?pl. provide sol.

1) 45
2) 54
3) 63
4) cannot be determined

Asked In MBA (12 years ago)

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tushar  (9 years ago)

Let us consider the division it would be x,y,z
Now
x+y=y+z+18(given)
x=z+18( let's us not run to the conclusion and say that z is 18)
x+y+z=90
x=z+18 (now there are two conclusions either y is the smaller part or z but not x)
Let us put first y as 18 and x as z+18
z+18+18+z=90
2z+36=90
2z=90-36
2z=54
z=27
So x = z+18
x=27+18
x=45

P.S since there are options 36,36,18 would not be a solution if this was a subjective question it could be challenging as this question has multiple number of solutions...

Is this solution Helpfull? Yes (2) | No   

Brij  (12 years ago)

Saara homework issi site par solve karwa loge kya ???:P

three parts are 36,36,18

if x is first part and 18 is third part, then 72-x is second part.
x+72-x= 18+(72-x)+18= 108-x
x=36

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