Latest MBA Aptitude Question SOLUTION: In how many ways can 600 be expressed as a sum of two or more consecutive natural numbers??(Need a simple approach to solve this)

1) 14
2) 7
3) 6
4) 5

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Previous Question: 2-(1/m)<4+(1/m) y satisfies this relation for positive integer values of m then the range of y is

1) 2<y<5
2) 2<y<=4
3) 1<y<=5
4) 2<=y<=4
Next Question: Three classes, A, B and C, have a total of 100 students. The students of all the three classes wrote a test. The average marks of all the three classes was 84, of A and B was 73 and of B and C was 87.5. Find the number of students in A, if the average marks of A and the average marks of C are 70 and 95 respectively.

1) 25
2) 30
3) 50
4) 20

(#M40017055) MBA question number systems, progressions Keep an EYE

In how many ways can 600 be expressed as a sum of two or more consecutive natural numbers??(Need a simple approach to solve this)

1) 14
2) 7
3) 6
4) 5

Asked In MBA (12 years ago)

Unsolved Read Solution (1)

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Read Solution (1) :

Indresh  (8 years ago)

4)5

By the preceding discussion, this is equal to the number of odd divisors of 600, minus one (to eliminate the trivial solution with one term.) The prime factorization of 600 is
600=2^3 3^1 5^2
and the number of odd divisors of 600 is (1+1)*(1+2) = 6. Therefore, there are 5 ways to write 600 as the sum of two or more consecutive positive integers.

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Previous Question: 2-(1/m)<4+(1/m) y satisfies this relation for positive integer values of m then the range of y is

1) 2<y<5
2) 2<y<=4
3) 1<y<=5
4) 2<=y<=4
Next Question: Three classes, A, B and C, have a total of 100 students. The students of all the three classes wrote a test. The average marks of all the three classes was 84, of A and B was 73 and of B and C was 87.5. Find the number of students in A, if the average marks of A and the average marks of C are 70 and 95 respectively.

1) 25
2) 30
3) 50
4) 20

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