Latest TCS Aptitude Question SOLUTION: A man jogs at 6 mph over a certain journey and walks over the same route at 4 mph. What is his average speed for the journey? (a) 2.4 mph (b) 4 mph (c) 4.8 mph (d) 5 mph

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A man jogs at 6 mph over a certain journey and walks over the same route at 4 mph. What is his average speed for the journey?
(a) 2.4 mph (b) 4 mph (c) 4.8 mph (d) 5 mph

Asked In TCS (13 years ago)

Solved jhinuk sikder Read Solution (11)

Is this Puzzle helpful?   (37)   (19) Submit Your Solution Time Distance and Speed

Read Solution (11) :

jhinuk sikder  (13 years ago)

we know x=6mph y=4mph
so average journey=2xy/(x+y)=48/10=4.8

Is this solution Helpfull? Yes (55) | No   

Dr.Dipin Singh  (13 years ago)

4.8 mph

suppose he travels 24 miles in one side.
he takes 4 hrs for jogging and 6 hrs for walking total distance of 48 miles.
Then av speed =48/10=4.8 mph

Is this solution Helpfull? Yes (25) | No (5)  

Rohit Srivastava  (13 years ago)

(2*6*4)/(6+4)=4.8

Is this solution Helpfull? Yes (11) | No (1)  

Tarun  (12 years ago)

avg speed= 2xy/ (x+y);
2*6*4/ (6+4)= 4.8.
if two different people have their different speed than we calculate avg speed by = (x+y)/2;
6+4 /2=5.

Is this solution Helpfull? Yes (7) | No (3)  

Pritam  (12 years ago)

t1=x/6 & t2=x/4
t1+t2=t=x/6 + x/4
hence,avg speed=(x/t)=2.4 mph

Is this solution Helpfull? Yes (3) | No (24)  

soujanya  (12 years ago)

(2*x*y)/(x+y)=28

Is this solution Helpfull? Yes (1) | No (9)  

R Santosh Kumar  (8 years ago)

given a man walking from one point to another point at a certain speed s1km/hr and then walking back the same route with a speed s2 km/hr then average speed for the journey is

average speed = (2s1s2)/(s1+s2)
i.e = (2*6*4)/(6+4)
= 4.8 mph
therefore c is the rt answer

Is this solution Helpfull? Yes (1) | No   

Tarun  (12 years ago)

avg speed= 2xy/ (x+y);
2*6*4/ (6+4)= 4.8.
if two different people have their different speed than we calculate avg speed by = (x+y)/2;
6+4 /2=5.

Is this solution Helpfull? Yes | No (3)  

rishu kant tiwari  (8 years ago)

v1v2/v1+v2=
2.4

Is this solution Helpfull? Yes | No (2)  

lavanya  (7 years ago)

when distance is constant,
avg speed=2*s1*s2/s1*s2;
avg speed=2*6*4/6+4;
=4.8

Is this solution Helpfull? Yes | No   

shuvendu ghosh  (4 years ago)

Average speed=(2*x*y)/(x+y)
4.8

Is this solution Helpfull? Yes | No   

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