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(#M40017664) IBM Numerical Ability question Keep an EYE

in a library there are 5 computer cluster open for public use.each computer cluster consist 33 laptop.in first week 75 laptop are used.in second week 155 laptop used ,in third week 30 laptop and in fourth week 160 laptop used.what fraction of library computer are in used in month?
a)3/5
b)2/7
c)2/3
d)1/14
e)1/4

Asked In IBM shagufta (11 years ago)

Unsolved Read Solution (14)

Is this Puzzle helpful?   (25)   (11) Submit Your Solution Ratio and Proportion

Read Solution (14) :

Aman  (11 years ago)

none of these

computer slots available in 4 weeks = 5*33*4= 660

computer slots used by public = 75+155+30+160 = 420

fraction of library computer are in used in month = 420/660 = 7/11

Is this solution Helpfull? Yes (82) | No (11)  

Lipismita Sahoo  (11 years ago)

answer is 2/3
because tota5l laptops=33*5=165
in first week used 75 menas 75 out of 165=75/165=15/33
2nd week 155/165=31/33
3rd week 30/165=6/33
4th week 160/165=32/33
total no of laptops whole month available=33*4=132
total no of laptops used=15+6+31+32=88
fraction=88/132=2/3

Is this solution Helpfull? Yes (23) | No (51)  

subha chakraborty  (9 years ago)

guyss (15+6+31+32=88)....please prove how u all r getting this?
Urgent..!!

Is this solution Helpfull? Yes (10) | No (6)  

anuj pradhan  (11 years ago)

No Grids=5
total number=5*33=165
sum of all the fractions over the month(Say X)=(75/165)+(155/165)+(30/165)+(160/165)

now fraction of computer used over month=X/4
i.e 2/3

Is this solution Helpfull? Yes (4) | No (29)  

saikumar k n v  (9 years ago)

answer is 2/3
because tota5l laptops=33*5=165
in first week used 75 menas 75 out of 165=75/165=15/33
2nd week 155/165=31/33
3rd week 30/165=6/33
4th week 160/165=32/33
total no of laptops whole month available=33*4=132
total no of laptops used=15+6+31+32=88
fraction=88/132=2/3
Dont confuse its correct answer!!

Is this solution Helpfull? Yes (4) | No (16)  

Himanshu  (9 years ago)

75+155+30+160 = 420

and the total books that can be used are 33*5*4 = 660

so the required answer is 420/660 which is 7/11.

Is this solution Helpfull? Yes (3) | No (5)  

sumn  (9 years ago)

total 5laptops=33*5=165
in first week used 75 menas 75 out of 165=75/165=15/33
2nd week 155/165=31/33
3rd week 30/165=6/33
4th week 160/165=32/33
total no of laptops used=(15+6+31+32)/33=88
fraction=(88/33)*1/4=2/3

Is this solution Helpfull? Yes (3) | No (7)  

Jakkana Sravani  (10 years ago)

can any one plz send solution.............

Is this solution Helpfull? Yes (2) | No (2)  

Debasish Bhunia  (8 years ago)

this question is ambiguous because it is not declared that all the laptops which are used in first week are also used in second week or some new from unused were used.this ambiguity is present in this question for all four weeks.
now my solution will go like this but i am not sure,
total laptops=33*5=165
i will assume that computers used in third week is also used in all other week.computers used in first week is also used2nd and 4th week.computers used in 2nd week is also used in 4th week.
 
so according to that total 160 out of 165 were used because 160 is highest in any week
so 160/165=32/33



another solution go like this.
total laptop available in a month=33*5*4=660
total laptop used in a month=75+155+30+160=420
so ans is 420/660=7/11

Is this solution Helpfull? Yes (2) | No (3)  

RAJU  (8 years ago)

yeah 2/3 is a right answer but most f u guys adding fractions separately for a week. find no of computer used for entire 4 weeks,and total no of computer available.so,420/165*4=7/11/=2/3.

Is this solution Helpfull? Yes | No (2)  

vijay  (8 years ago)

5*33=165 laptops
In first week 75 laptops were used and laptops are not use and throw
In second week 155 laptops were used (In which 75 were reused)
In third week 30 ..
In fourth 160 laptops were used..
Fraction=No of laptop used /Total no of laptop
=160/165
=32/33

Is this solution Helpfull? Yes | No (1)  

raja singh  (7 years ago)

this question is ambiguous because it is not declared that all the laptops which are used in first week are also used in second week or some new from unused were used.this ambiguity is present in this question for all four weeks.
now my solution will go like this but i am not sure,
total laptops=33*5=165
i will assume that computers used in third week is also used in all other week.computers used in first week is also used2nd and 4th week.computers used in 2nd week is also used in 4th week.

so according to that total 160 out of 165 were used because 160 is highest in any week
so 160/165=32/33

another solution go like this.
total laptop available in a month=33*5*4=660
total laptop used in a month=75+155+30+160=420
so ans is 420/660=7/11

But none of these is in the option

Is this solution Helpfull? Yes | No   

shabana  (7 years ago)

Given computer xluster open for public = 5
So, Total laptops = 33*5=165
In first week used 75 menas 75 out of 165=75/165=15/33
2nd week 155/165=31/33
3rd week 30/165=6/33
4th week 160/165=32/33
So. Total no of laptops used=(15+6+31+32)/33=88
Fraction of library computer are in used = (88/33)*1/4=2/3

Is this solution Helpfull? Yes | No   

Neha Shahid  (6 years ago)

420/660=11/7

Is this solution Helpfull? Yes | No   

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