Latest Elitmus Aptitude Question SOLUTION: A horsecarter has two wheels,frontwheel nd bachwheel...nd their circumference r in the ratio x:y. frontwheel take T rotations in one min nd backwheel takes T+x rotation in one minu

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(#M40017889) ELITMUS Numerical Ability question Keep an EYE

A horsecarter has two wheels,frontwheel nd bachwheel...nd their circumference r in the ratio x:y. frontwheel take T rotations in one min nd backwheel takes T+x rotation in one minute.T,x,y r integers >0..so fing the second least value of y...when y>x?

Asked In Elitmus Mukesh Kr Singh (11 years ago)

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Aman  (11 years ago)

least integral value of y = 1
second least value = 2
Tx= (T+x)*y
y= Tx/(T+x)
so y=1, when T=x=2
y=2, when T=x=4

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krishna yadav  (11 years ago)

Tx=(T+x)y
=>y=T/(1=T/x)
as y>x and x>0
so x=1,y=2
=>T=2(T>0)
=>Y=2

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farjana sayyed  (10 years ago)

but guys,,
here given that y>x,,
but you got y

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jaspreet  (11 years ago)

its given y>x,which implies that the ratio x:y is for backwheel:frontwheel.then (T+x)x=Ty.if Tx=(T+x)y,then:xy=T(x-y) which will be negative,as y>x,which is not possible.
now if Tx+x^2=Ty.so x^2=T(y-x).so second least value comes out to be 3.then with x=2,T=4.y cannot be 1.so least value will be 2.

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Sumit Rawal  (10 years ago)

@aman by the way u have done the question the 2nd least value of y is 2 only possible put T=3,x=6 i.e. 3*6/3+6 ie. 18/9=2

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