Latest self Aptitude Question SOLUTION: find the probability distribution of the number of successes in two tosses of a die, where a success is defined as i) no. greater than 4 ii) 6 appears on at least one die

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(#M40017897) SELF question Keep an EYE

find the probability distribution of the number of successes in two tosses of a die, where a success is defined as
i) no. greater than 4
ii) 6 appears on at least one die

Diksha Malhotra (11 years ago)

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nishant aggarwal  (11 years ago)

1. 8/9
2. 1/3

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jatin  (11 years ago)

(i) Sample space is 1,2,3,4,5,6
probability of getting no. greater than 4 in firs toss is 2/6 =1/3
so probability of getting no. less than 4 is 1-1/3=2/3
Let X denote the no of successe in two tosses of a die. Then x can be 0,1,2
so p(X=0)=probability of no success in first and 2nd toss both =2/3*2/3=4/9
p(X=1)=prob. of success in first and failure in 2nd or vice versa.
= 1/3*2/3+2/3*1/3=4/9
p(x=2)= prob. of success in both toss =1/3*1/3 =1/9
so probability dist. is
X; 0 1 2
P(X); 4/9 4/9 1/9

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srinivasulareddy  (11 years ago)

1)2/6*2/6=1/9
2)1/6+1/36=7/36

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