Latest self Aptitude Question SOLUTION: Samrat Ashok had 10 chiefs, each of whom had to pay obeisance to him. The chiefs were numbered from 1 to 10 and the chief numbered N had to give him N gold coins each weighing 10

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(#M40018382) SELF question APTI Keep an EYE

Samrat Ashok had 10 chiefs, each of whom had to pay obeisance to him. The chiefs were numbered from 1 to 10 and the chief numbered N had to give him N gold coins each weighing 10 gms. The total weight of all coins received turned out to be 532 gms. Ashok's mantri suspected that one of the chiefs had submitted all coins weighing 20% less. The possibility of more than one chief cheating does not exist. Based on this information, we can conclude that
Ops: A. No one had cheated and the mantri was unnecessarily worried
B. Either chief number 6 or chief number 8 had cheated
C. Chief number 9 had cheated
D. It is impossible to find out who had cheated Samrat Ashok

vikash kumar shukla (11 years ago)

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Sagnya Tripathy  (11 years ago)

C.chief no. 9 had cheated

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jassi  (9 years ago)

Each chief pays his number multiplied by 10 gms
For example 1st one 10, 2nd one 20, 3rd one 30 and the last - 10th one 100gms. Total number should have been ((10*11)/2) * 10gms = 550gms. King should have got 550gms but got only 532gms, meaning 18 gms are missing.
A - So, definitely someone has cheated. So this is wrong.
B - 6 should have paid 60. 20% of 60 is 12. King is missing more than 12 gms. Similarly, 8 should have paid 80. 20% of 80 is 16 gms. So this is also incorrect.
C- 9 should have paid 90. 20% of 90 is 18gms, which is exactly the same as what king is missing. So this is the right answer.
D- We already know 9th chief is the culprit.

So C is the right answer

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