Latest self Aptitude Question SOLUTION: AC2,CG5,FL9,JR14,OY20,____

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(#M40018463) SELF question Complete the series Keep an EYE

AC2,CG5,FL9,JR14,OY20,____

Devendra Marghade (11 years ago)

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chandu  (11 years ago)

ANS:UG27
A+2=c,c+3=f........o+6=u(first letter)
c+4=g,g+5=l........y+8=G(second letter)
U=21,g=33,u+g=54/2=27 or 2+3=5,5+4=9,9+5=14,14+6=20,20+7=27(3rd letter)

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Chandni Maurya  (10 years ago)

ans=UG27
First letter: A+2=C;C+3=F;F+4=J;J+5=O; Next=> O+6=U
Third digit: 2+3=5;5+4=9;9+5=14;14+6=20; Next=> 20+7=27
Second letter: 2+1=3=C;5+2=7=G;9+3=12=L;14+4=18=R;20+5=25=Y; Next=> 27+6=33
=(33-26)
=7
=G

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Udhaya kumar  (11 years ago)

A=1,C=3 1+3=4/2=2..2+1=3=C(NEXT STARTING)
2,5,9,14,20 DIFFERENCE OF 3,4,5,6 THEN 7... FIRST LETTER IS 21=T
SO ANSWER IS ==== T(33RD ALPHABET)27....
QUESTION IS WRONG.......

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chakrapni  (11 years ago)

zb27 before we have ac2=1+3/2=2,3+7=5 so cg5 and difference between is 3,4,5,6,7
so we should get 27 as last so we have to get 54 so we should take alphabets which leads to a sum of 54 so i have taken z=26 and completing all alphabets and coming again from starting we get b=28 so 26+28/2=27

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