Latest Wipro Aptitude Question SOLUTION: . a man speaks 3 out of 4 times.he throws a dice n report it to be 6 what is probability of being 6

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(#M40018684) WIPRO Numerical Ability question Keep an EYE

. a man speaks 3 out of 4 times.he throws a dice n report it to be 6 what is probability of being 6

Asked In Wipro janvi sahu (10 years ago)

Unsolved Read Solution (13)

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Read Solution (13) :

vinod  (10 years ago)

man speaks truth 3 out of 4 times=3/4
probability of getting 6 on throwing a dice is 1/6
so reqd prob=(3/4)*(1/6)=1/8

Is this solution Helpfull? Yes (29) | No (5)  

niraj kumar  (10 years ago)

it should be speak truth 3 out of 4.
prob. of true speak=3/4,prob.of flase speak=1/4
prob. of getting 6=1/6
prob. of not getting 6=5/6
so prob=(3/4*1/6)/3/4*1/6+5/6*1/6
ans=3/8

Is this solution Helpfull? Yes (9) | No (7)  

ADHOKSH  (10 years ago)

GUYZ WHICH ONE 3/8
OR 1/8
M CONFUSED?????????????

Is this solution Helpfull? Yes (5) | No (1)  

leelavathi  (10 years ago)

man speaks truth 3 out of 4 times, probability=3/4
probability of man speaking false = 1-3/4 =1/4
probability of getting 6 on dice=1/6
probability of not getting 6 on a dice= 1-1/6 = 5/6
therefore reqd probability= (3/4)(1/6)/ (3/4)(1/6)+(1/4)(5/6)
= 3/8

Is this solution Helpfull? Yes (4) | No (1)  

mukesh  (10 years ago)

probability of being six is= 3/4*1/6
=1/8

Is this solution Helpfull? Yes (3) | No (2)  

arjun  (10 years ago)

probability of getting a die is=1/6
and the speaks 3/4 times so
probablity of being six=(1/6)*(3/4)=1/8

Is this solution Helpfull? Yes (2) | No (2)  

sudhanshu shekhar  (10 years ago)

it should be speak truth 3 out of 4.
prob. of true speak=3/4,prob.of flase speak=1/4
prob. of getting 6=1/6
prob. of not getting 6=5/6
so prob=(3/4*1/6)/3/4*1/6+5/6*1/6
ans=3/8

Is this solution Helpfull? Yes (2) | No (3)  

Divya Buddha  (10 years ago)

options-A) 3/4
B) 5/8
C) 2/5
D) 3/5
E) 4/5
Prob that its a 6 and he speaks truth :- 3/4 * 1/6 = 3/24

Now what is the prob of reporting a 6 on a dice when it is a lie = 1/4 (speaking a lie) * 5/6 (prob of no. other than 6) * 1/5 (lieing the number as 6 and not telling any othe number except the actual no.) = 5/120 = 1/24

Thus the prob of reporting no. as 6 (total lie + truth) = 3/24 + 1/24 = 4/24 = 1/6

Thus prob of actually having 6 when reported so is = 3/24/1/6 = 3/4

Answer A.

Is this solution Helpfull? Yes (2) | No   

nitu kumari  (10 years ago)

3/4*1/6=1/8

Is this solution Helpfull? Yes (1) | No (2)  

anand kumar  (10 years ago)

probability of getting 6 =1/6
probability of a speaking truth =3/4
so probability that a got 6 is= (3/4)*(1/6)= 1/8

Is this solution Helpfull? Yes (1) | No (2)  

mounika  (10 years ago)

they asked only the probability of being 6.so i guess ans is 1/8

Is this solution Helpfull? Yes (1) | No (1)  

Sohini Nandi  (10 years ago)

If 6 actually appeared, he can report it with the probability of 3/4. If 6 has not appeared, still he can report it wrongly with the probability of 1/4
So the probability that it is actually a 6 = (Probability to appear 6 x His truthfulness to report + Probability to appear any other number x His lieing probability ) = (1/6×3/4)+(5/6×1/4)=1/3
The probability that it is actually 6 = (Probability that he reports 6)/(Total probability to appear 6)=(3/4×1/6)/((3/4×1/6)+(1/4×5/6))=3/8

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mahesh yadav  (8 years ago)

Prob that its a 6 and he speaks truth :- 3/4 * 1/6 = 3/24

Now what is the prob of reporting a 6 on a dice when it is a lie = 1/4 (speaking a lie) * 5/6 (prob of no. other than 6) * 1/5 (lieing the number as 6 and not telling any othe number except the actual no.) = 5/120 = 1/24

Thus the prob of reporting no. as 6 (total lie + truth) = 3/24 + 1/24 = 4/24 = 1/6

Thus prob of actually having 6 when reported so is = 3/24/1/6 = 3/4

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