Latest Infosys Aptitude Question SOLUTION: Mr. ANYMAN left ANYTOWN by car to attend a wedding at ANYCITY. He had been driving for exactly two hours when the car got punctured. It took his driver exactly ten minutes to chan

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Mr. ANYMAN left ANYTOWN by car to attend a wedding at ANYCITY. He had been driving for exactly two hours when the car got punctured. It took his driver exactly ten minutes to change the wheel. In order to play safe they covered the remaining distance at a speed of 30 mph. consequently, Mr. ANYMAN was at wedding half an- hour behind schedule. Had the car got the puncture only 30 miles later , I would have been only FIFTEEN minutes late he told the driver . How Far is ANYCITY from ANYTOWN.

Asked In Infosys Aditi Sharma (12 years ago)

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bhajan preet singh  (12 years ago)

120 m is the answer..

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bindu  (10 years ago)

first he took total time=2+t+10/60 where t is the time taken to travel after puncture
in the second case the total time=2+30/s+10/60+t-15/60 where 30/s is the time taken to move 30 miles before puncture and 15/60 is that if we fast we will be 15mins before so we need to subtract
so solving both s=120mph
x=240miles
before puncture we have travelled 240
30=d-x/t
30=d-240/t
30t=d-240 from
30=d-(x+30)/t-15/60
d-240/t=(d-270)/t-(1/4)
by solving we get values of d and t

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