Latest TCS Aptitude Question SOLUTION: roy is now 4 years older then erik and half of that amount older than iris.If in 2 years, roy will be twice as old as erik,then in 2 years what would be roy's age multiplied by iri

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roy is now 4 years older then erik and half of that amount older than iris.If in 2 years, roy will be twice as old as erik,then in 2 years what would be roy's age multiplied by iris's age?

Asked In TCS Anupam pandey (10 years ago)

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anjul meid  (10 years ago)

48....R=E+4;R=I+(4/2);(R+2)=2(E+2) solving R=6;I=4;E=2;so after 2 years ( R+2)(I+2)=(8)(6)=48

Is this solution Helpfull? Yes (20) | No (13)  

manoj kumar jha  (10 years ago)

let r is roy's age,e erics age and i is iris age.
than,
roy is 4 years older then erik
r=e+4;
roy is half of that amount older than iris
i.e. r = i+(e+4)/2;
after 2 yrs,
r+2=2e+4
r+2=2(e+2)
r+2=(2e+4)
r=2e+2
r=2(r-4)+2
r=2r-8+4
r=6
e=2
i=3
so in 2 years roy's age multiplied by iris's age=(r+2)*(i+2)
=8*5=40

Is this solution Helpfull? Yes (10) | No (6)  

priyanka  (10 years ago)

consider erik age as x, then roy age will be 4+x and iris age will be 8+2x. after two yrs by qn roy age is 2(x+2) since erik age becomes x+2. we knw that roy age 4+x so aftr 2 yrs 6+x, equate both we get x=2. substitute it we get roy age as 8, iris age as 14 multiplying it we get ans as 112

Is this solution Helpfull? Yes (2) | No (4)  

k.m  (10 years ago)

current age of roy nd iris is 6,4 so 6*4=24 then after 2 year 8*6=48

Is this solution Helpfull? Yes (2) | No (2)  

shailesh kumar mishra  (10 years ago)

4/3since r=6 and i=4 after 2
r=8,i=6

Is this solution Helpfull? Yes (1) | No (2)  

venkatasaisharan  (8 years ago)

R=E+4,R=I/2 AFTER 2 YEARS R+2=2(E+2) ON SOLVING WE GET E=4,R=8,I=16 AND AFTER 2 YEARS R=10 AND I=18 SO ANS IS 180

Is this solution Helpfull? Yes (1) | No (2)  

niket pandey  (10 years ago)

24..by solving

Is this solution Helpfull? Yes | No (5)  

aditya vasudeva  (8 years ago)

48 is the correct answer

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sagar kumar  (8 years ago)

roy=r,erik=e,irik=i
r=e+4---------------------------(1)
r=(e+4)/2+i
after 2 yr
r+2=2(e+2)
r=2e+6 --------------------(2)
euating 1&2 and solving we e=2r,=6,i=3 after 2 yr e=4 r=8 and e*r=8*6=48(ans)

Is this solution Helpfull? Yes | No (1)  

aditya raj  (7 years ago)

Roy =(x/2)+4 ,Erik=x/2 ,Irish=x
then ( x/2)+4+2=x+4
then x=4
hence after 2 years roy is 8 and irish is 6
soroy is 3/2 times irish

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Sudharsan  (7 years ago)

Let Roy's age be x
Then Erik's age=x-4;
Iris' age= x-2;
In 2 years roy will be twice as old as erik i.e.
x+2=2(x-4+2);
Solving we get x=6 i.e. Roy's age=6yrs and Iris age=4;
in 2 years what would be roy's age multiplied by iris's age:
[Roy's age in 2 yrs]*[Iris' age in 2yrs]=(6+2)*(4+2)=48;

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