Latest TCS Aptitude Question SOLUTION: If the sides of a triangle measure 72, 75 and 21, what is the measure of its in radius?

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40019114) TCS question Keep an EYE

If the sides of a triangle measure 72, 75 and 21, what is the measure of its in radius?

Asked In TCS Perumalsamy (10 years ago)

Unsolved Read Solution (3)

Is this Puzzle helpful?   (17)   (10) Submit Your Solution

Read Solution (3) :

yogesh kumar yadav  (10 years ago)

The sides of the triangle happen to be a Pythagorean triplet.
Hence, the triangle is a right angled triangle.

For a right angled triangle,
The measure of in radius = (product of perpendicular sides) / (perimeter of triangle)

= (72 * 21) / (72 + 21 +75) = 1512 / 168 = 9

Is this solution Helpfull? Yes (24) | No   

nitish raj  (10 years ago)

72^2+21^2=75^2;so,72,21,75 are sides of right angle triangle. in a circle, right angle triangle's hypotense passes thru centre. so ,75 is diameter.
radius=75/2=37.5

Is this solution Helpfull? Yes (8) | No (6)  

Nidhi N  (10 years ago)

this triangle is a right angled triangle
so the measure of radius is calculated using the formula
(product of perpendicular sides)/(perimeter of the triangle)
so it is (72*21)/(72+75+21)
1512/168
=9
9 is the radius

Is this solution Helpfull? Yes (4) | No   

Please Login to Read Solution.