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(#M40019114) TCS question Keep an EYE

If the sides of a triangle measure 72, 75 and 21, what is the measure of its in radius?

Asked In TCS Perumalsamy (11 years ago)

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yogesh kumar yadav  (11 years ago)

The sides of the triangle happen to be a Pythagorean triplet.
Hence, the triangle is a right angled triangle.

For a right angled triangle,
The measure of in radius = (product of perpendicular sides) / (perimeter of triangle)

= (72 * 21) / (72 + 21 +75) = 1512 / 168 = 9

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nitish raj  (11 years ago)

72^2+21^2=75^2;so,72,21,75 are sides of right angle triangle. in a circle, right angle triangle's hypotense passes thru centre. so ,75 is diameter.
radius=75/2=37.5

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Nidhi N  (11 years ago)

this triangle is a right angled triangle
so the measure of radius is calculated using the formula
(product of perpendicular sides)/(perimeter of the triangle)
so it is (72*21)/(72+75+21)
1512/168
=9
9 is the radius

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