Latest Infosys Aptitude Question SOLUTION: There are 3 societies A, B, C having some tractors each. A Gives B and C as many tractors as they already have. After some days B gives A and C as many tractors as they have. Afte

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There are 3 societies A, B, C having some tractors each. A Gives B and C as many tractors as they already have. After some days B gives A and C as many tractors as they have. After some days C gives A and B as many tractors as they have. Finally each has 24 tractors. What is the original Number of tractors each had in the beginning? Ans. A ?39. B? 21. C? 12.

Asked In Infosys sawan kumar (12 years ago)

Unsolved Read Solution (3)

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Read Solution (3) :

akanksha tripathi  (10 years ago)

Let us take in the reverse order,

all A, B & C each has 24 remaining at the end.

A B C
24 24 24

before C gave to A & B the had
A B C
12 12 24+12+12=48

now before b gave A & C the same amount of tractor they already had

A B C
6 12+6+24=42 24

Now befor A gave B & C, they must had

A B C
6+21+12=39 21 12

A=39, B=21, C=12

Is this solution Helpfull? Yes (21) | No (1)  

  (5 years ago)

before starting t solve this question i would like to say you should have t know about backtracking technique so,

last
A=24 B=24 c=24
okay
now just see last c option means last person who give tractors okay
so last one is c
after c gave tractors how much he have
so divide a/2=12
b/2=12
now add
C=12+12+24;
C=48
now sales method on B
a/2=6
c/2=24
B=6+12+24=42;
now again use this method
for A
b=42/2=21
c=24/2=12
A=12+21+6=39

now initial they
have
A=39 B=21,C=12

hope you get your answers please like and share

Is this solution Helpfull? Yes (1) | No   

kandy  (10 years ago)

A B C
24 24 24 (at the end)
12 12 24+12+12
6 12+6+24 24+12+12
6+12+6+12+3 12+6+3 12

Is this solution Helpfull? Yes | No (4)  

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