The first two terms of a series are a and b respectively a b 0 and thereafter every subsequent term

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(#M40019386) OTHERS question Keep an EYE

The first two terms of a series are ‘a’ and ‘b’ respectively, (a, b > 0) and thereafter, every subsequent term is the average of the previous two terms. What is the 12th term of this series?

options

a--(171a + 341b)/512
b--(343a + 681b)/1024
c--(341a + 683b)/1024
d--(683a + 1365b)/2048: Asked In Others mohan lal garg (11 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Latest Others Aptitude Question SOLUTION: The first two terms of a series are ‘a’ and ‘b’ respectively, (a, b > 0) and thereafter, every subsequent term is the average of the previous two terms. What is the 12th te

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(#M40019386) OTHERS question Keep an EYE

The first two terms of a series are ‘a’ and ‘b’ respectively, (a, b > 0) and thereafter, every subsequent term is the average of the previous two terms. What is the 12th term of this series?

options

a--(171a + 341b)/512
b--(343a + 681b)/1024
c--(341a + 683b)/1024
d--(683a + 1365b)/2048

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Latest Others Aptitude Question SOLUTION: The first two terms of a series are ‘a’ and ‘b’ respectively, (a, b > 0) and thereafter, every subsequent term is the average of the previous two terms. What is the 12th te

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(#M40019386) OTHERS question Keep an EYE

The first two terms of a series are ‘a’ and ‘b’ respectively, (a, b > 0) and thereafter, every subsequent term is the average of the previous two terms. What is the 12th term of this series? options a--(171a + 341b)/512 b--(343a + 681b)/1024 c--(341a + 683b)/1024 d--(683a + 1365b)/2048

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The first two terms of a series are ‘a’ and ‘b’ respectively, (a, b > 0) and thereafter, every subsequent term is the average of the previous two terms. What is the 12th term of this series?

options

a--(171a + 341b)/512
b--(343a + 681b)/1024
c--(341a + 683b)/1024
d--(683a + 1365b)/2048