Latest TCS Aptitude Question SOLUTION: Derek throws three dice in a special game. If it knows that he needs 15 or higher in this throw to win, then find the chance of his winning the game. A.5/54 B.17/216 C.13/216

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(#M40019649) TCS Numerical Ability question Keep an EYE

Derek throws three dice in a special game. If it knows that he needs 15 or higher in this throw to win, then find the chance of his winning the game.

A.5/54

B.17/216
C.13/216
D.15/216

Asked In TCS (10 years ago)

Unsolved Read Solution (13)

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Read Solution (13) :

vaaspandi  (10 years ago)

THINK THROUGH BEFORE TAKE CHOICE..ULTIMATE ANSWER WILL BE ALWAYS HIGHER IN PROBABILITY..

TO WIN THE GAME HE HAVE TO GET 15 OR HIGHER (ie:16,17,18)

SO CALCULATE CHOICES FOR THE NUMBERS 15,16,17,18.

15=555 456 465 546 564 645 654 366 636 663
16=466 646 664 556 565 655
17=665 656 566
18=666

TOTAL=20
TOTAL WAYS WHILE THROWING 3 DICES: 6*6*6=216

SO CHANCE OF GETTING 15 OR HIGHER WILL BE AS FOLLOWS

20/216=5/54.

OPTION A IS RIGHT ANSWER.

Is this solution Helpfull? Yes (40) | No (1)  

chappidiprudvi  (10 years ago)

option a is the right answer 5/54 (5,4,6)(15) can be arranged in 6 ways
(5,5,6)(16) can be arranged in 3 ways.(5,5,5)(15)in 1 way (6,6,6)(18) in 1 way (6,6,5)(17)in 3 ways (6,6,4)(16)in 3 ways (6,6,3)(15)in 3 ways totally 6+3+1+1+3+3+3=20 so propab is 20/(6^3)=20/216=5/54

Is this solution Helpfull? Yes (8) | No (2)  

k.m  (10 years ago)

i think answer is 15/216.because there is (5,5,5)(4,5,6)(3,6,6)(6,4,5)(5,4,6)(6,3,6)(6,5,4)(6,6,3)(4,6,6)(5,6,6)(6,6,6)(6,4,6)(6,5,6)(6,6,4)(6,6,5)=15 ways
so 15/216

Is this solution Helpfull? Yes (8) | No (3)  

JAGYANDUTTA CHOUDHURY  (10 years ago)

Here n(S)=6*6*6=216;
E=Event of getting a total 15 or more than 15={555,556,565,566,564,546,456,465,466,366,666,665,656,664,646,654,645,663,636,655}
=20
that is 20/216=54/216

Is this solution Helpfull? Yes (5) | No   

dilep gautam  (10 years ago)

THINK THROUGH BEFORE TAKE CHOICE..ULTIMATE ANSWER WILL BE ALWAYS HIGHER IN PROBABILITY..

TO WIN THE GAME HE HAVE TO GET 15 OR HIGHER (ie:16,17,18)

SO CALCULATE CHOICES FOR THE NUMBERS 15,16,17,18.

15=555 456 465 546 564 645 654 366 636 663
16=466 646 664 556 565 655
17=665 656 566
18=666

TOTAL=20
TOTAL WAYS WHILE THROWING 3 DICES: 6*6*6=216

SO CHANCE OF GETTING 15 OR HIGHER WILL BE AS FOLLOWS

20/216=5/54.

OPTION A IS RIGHT ANSWER.

Is this solution Helpfull? Yes (4) | No   

HARSH  (10 years ago)

to win the game Derek needs either 15,16,17 or 18 more than 18 not possible with 3 Dice(6+6+6=18).
Dice1 Dice2 Dice3 Arrangement
3 6 6 3!/2=3 (out of 3 , 2 are same that's divide by 2)
4 5 6 3!=6(all are different)
4 6 6 3!/2=3(same as in 3,6,6)
5 5 5 1(all are same)
5 5 6 3!/2=3
5 6 6 3!/2=3
6 6 6 1

number of events=3+6+3+1+3+3+1=20
probability=no. of events/total out comes
=20/6^3
=20/216=>5/54

Is this solution Helpfull? Yes (2) | No   

Robin Kumar  (10 years ago)

366,466,465,456,566,565,556,546,564,666,665,656,646,664,636,663,654,645,655
total 19 ways possible
so required probability=19/216
since no option is matching the answer should be NONE OF THESE. Correct me if i'm wrong

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chaitra.m  (10 years ago)

b is the answer.if we throw a dice,there are 216 possibilities inorder to get 15 or higher (4,6,6)(6,4,4)(6,6,4)(...........like this v get the combination of 4,5,6 and 5,5,6 and 5,6,6 and 5,5,5, and 6,6,6

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Sarthak Gupta  (10 years ago)

17/216
555 556 565 655 666 645 546 564 456 465 654 663 366 636 664 466 646

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sheshan bhardwaj  (10 years ago)

17/216 coz (366 456 665 466 556) three times so total=15 +(555 666 ) one time so total of 17 ways

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aryan  (10 years ago)

20 cases
so 20/216

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nisha sengar  (10 years ago)

17/216
(6,6,6),(5,5,5),(6,3,6)-all combination=3,(4,5,6)-all 6 combination=6,(6,6,5)-all three com.=3,(6,5,5)-all three com.=3.
total com.=17
no of total chances=216
so, chances of winning=17/216

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khushboo bansal  (10 years ago)

its 17/216. expanding all the possibilities.

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