Latest self Aptitude Question SOLUTION: find the number of consecutive zeroes at the end of 100!*200!*300!

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(#M40019716) SELF question Keep an EYE

find the number of consecutive zeroes at the end of 100!*200!*300!

preeti sinha (10 years ago)

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Sahil  (10 years ago)

147

there is a property for such type of questions
like if u have to find no. of zeroes in 100!

100/5=20(integer part) + 100/sq(5)=4(integer part) so 24 zeroes in 100!

similarly for 200!
200/5=40 + 200/25=8 + 200/125=1 so 49 zeroes in 200!

nd for 300!
300/5=60 + 300/25=12 + 300/125=2 so 74 zeroes

by multiplying all...we will sum all zeroes so 147 is answer!!

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shajid khan  (9 years ago)

Can anybody answer this how many cosecutive zeroes in 100!+200!?
I have solved it as 100! Has 24 zeros and 200! Has 49 zeros at last I added them the answer will be 73 but in the book it is given 24..how?

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