Latest 3i-Infotech Aptitude Question SOLUTION: A man buys 12 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 10 lts of another mixture with 30% of liquid. What is the % of water in th

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A man buys 12 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 10 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?

Asked In 3i-Infotech sawan kumar (12 years ago)

Solved suchandra raavi Read Solution (4)

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suchandra raavi  (12 years ago)

20% in 12 lts is 2.4. So water = 12-2.4 = 9.6 lts. 30% of 10 lts = 3. So water in 2nd mixture = 10-3 = 7 lts. Now total quantity = 12 + 10 = 22 lts. Total water in it will be 9.6 + 7 = 16.6 lts. % of water = (100*16.6)/22 = 75.45

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dhanalakshmi  (10 years ago)

liquid after mixing = 12/5 + 3 = 5.4ltr

% of liquid = (5.4/22)*100
= 24.5%

% of water = 100 - 24.5

=75.5%

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pragya saxena  (7 years ago)

firstly ,in 12 litre
ratio of liquid and water is 1:4 -> so part of water in this -> 4/5*12=48/5 litre

now in 10 litre
ratio of liquid and water is 3:7 -> so part of water in this -> 7/10*10= 7litre
After adding both we get --> (7+(48/5)) = 83/5 litre water and after adding mixture has become =22 litre
so percent of water in 22 litre is --> ((83/5*22)*100) = 75.45% Ans.

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Nishchay Pathak  (6 years ago)

% of Liquid in Solution A = 20%

⇒ % of Water in Solution A = 80%

Volume of Solution A = 12 Litres

⇒ Volume of Water in Solution A = (80/100) × 12 = 9.6 Litres

% of Liquid in Solution B = 30%

⇒ % of Water in Solution A = 70%

Volume of Solution B = 10 Litres

⇒ Volume of Water in Solution B = (70/100) × 10 = 7 Litres

If Solution A is mixed with Solution B

⇒ Net Total Volume of Solution = (12 + 10) = 22 Ltrs

⇒ Net Total Volume of Water in Solution = (9.6 + 7) = 16.6 Ltrs

% of Water in New Mixture = (Volume of Water in New Mixture / Volume of New Mixture) × 100

% of Water in New Mixture = (16.6 / 22) × 100 = 75.45%

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