Latest 3i-Infotech Aptitude Question SOLUTION: Pipe A can fill a tank in 30 mins and Pipe B can fill it in 28 mins.If 3/4th of the tank is filled by Pipe B alone and both are opened, how much time is required by both the pipes

• Placement Papers
• /
• 3i-Infotech
• /
• Numerical Ability
• /
• Time and Work

3i-Infotech Question Papers: 3I-INFOTECH Company Profile

(#M40002012) 3I-INFOTECH Numerical Ability question placement question Keep an EYE

Pipe A can fill a tank in 30 mins and Pipe B can fill it in 28 mins.If 3/4th of the tank is filled by Pipe B alone and both are opened, how much time is required by both the pipes to fill the tank completely ?

Asked In 3i-Infotech sawan kumar (12 years ago)

Unsolved Read Solution (4)

Is this Puzzle helpful?   (27)   (5) Submit Your Solution Time and Work

Read Solution (4) :

ganesh  (10 years ago)

Pipe A filling rate:1/30 tank/min

Pipe B filling rate:1/28 tank/min

Combined filling rate: 1/30 + 1/28 tank/min

Together they fill 1/4 of the tank. Let t be the time required.

(1/30 +1/28)t = 1/4

t = (1/4)(30*28)/(28+30) = 105/29 min ~ 3.62 min


Answer:3.62 min is required by both the pipes to fill the tank completely.

Is this solution Helpfull? Yes (22) | No (6)  

Harsh Sharma  (10 years ago)

pipe A fill 1/30 in 1 mnt.
similarly pipe B fill 1/28 in 1mnt
3/4th part is filled by pipe B alone.
so time taken by pipe B to fill 3/4th part will be.
( 1/28 ---------- 1mt
3/4 ----------- x mnt
by cross multiplication
1/28 * x =3/4
so x=(28*3)/4 = 21 mnts)
so B takes 21mnts to fill 3/4th part alone...
now the remaining part is
1-3/4 = 1/4.
now, (A+B)'s 1mnt work = 1/30 + 1/28 = 29/420.
therefore time taken by both pipes to fill 1/4th part together will be..
( 29/420-------- 1mnt
1/4----------- x mnt
by cross multiplication
x = 420/(29*4)
x= 105/29 = 3.62 mnts)..
so the total time taken by both the pipes to fill the tank is
(time taken by pipe B to fill 3/4th part + time taken by both pipe to fill 1/4th part)
21+3.62=24.62 mnts

Is this solution Helpfull? Yes (21) | No (1)  

surojit saha  (12 years ago)

time required by pipe A=1/4/1/30=30/4
time required by pipe B=3/4/1/28=21
so total time required=30/4+21=28.5

Is this solution Helpfull? Yes (9) | No (25)  

KAGITHA T N V SIVA KARHIK  (7 years ago)

T w
A 30 28
840
B 28 30

1-3/4=1/4

840/4=210 (remain work)

210/(30+28)=3.62min

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.