Latest reasoning Aptitude Question SOLUTION: Find the 3 digit no. whose last digit is the square root of the first digit and second digit is the sum of the other two digits. And that number is divisible by 2,3,6,7.What is tha

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(#M40020235) REASONING Numerical Ability question Keep an EYE

Find the 3 digit no. whose last digit is the square root of the first digit and second digit is the sum of the other two digits.
And that number is divisible by 2,3,6,7.What is that number?

Asked In reasoning AISHWARYA (10 years ago)

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RAKESH  (10 years ago)

let xyz be the digits of no.,then
z=sqrt(x)
y=x+z=x+sqrt(x)
so no. is =100x+10y+z
=100x+10(x+sqrt(x))+sqrt(x)
=110x+11*sqrt(x)
if x=1, no. is =121
if x=4, no. is =462
if x=9, no. is =990+33=1023(not 3 digit)
two no's 121 & 462
now no. is divisible by 2,3,6,7
so divisible by LCM OF 2,3,6,7 = 42
only 462 is divisible by 42
ANS 462

Is this solution Helpfull? Yes (3) | No (1)  

Nandikesh  (9 years ago)

as the no is of only 3 digit so it can be 2 or 3 and this no should be divisible by 2 so last digit is fix i.e 2 so ans will be 462

Is this solution Helpfull? Yes (3) | No (1)  

siva  (9 years ago)

If z=squr(x),
. y=x+z.
If x=4=>z=2
Y=x+z=>4+2=6
So.num is 462

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manthena naveen kumar  (7 years ago)

462
sqr root of 4 is 2
sum of 4 and 2 is 6
and 462 is div by 2 3 6 7

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Ravindra Reddy  (5 years ago)

lcm(2,3,6,7)=42
4+2=6(second number
462

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