Latest Infosys Aptitude Question SOLUTION: find sum of 3+5/(1+2^2)+7/(1+2^2+3^2)+.......

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find sum of 3+5/(1+2^2)+7/(1+2^2+3^2)+.......

Asked In Infosys MAN (10 years ago)

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soujanya kolukuluri  (10 years ago)

this is in da form of summation of terms each in form of [(2n+1)/(1^1+2^2+...n^n)]
where n is from 1 to infinity
1^1+2^2+...n^n=[n*(n+1)*(2n+1)]/6
so,(2n+1)/(1^1+2^2+...n^n)=sigma of [6/(n*(n+1))]
=6[(1/(2*3))+(1/(2*3))....]
=6[(1/1-1/2)+(1/2-1/3)+....]
=6
therefore ans is 6

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ABHAY KUMAR  (10 years ago)

6
do the partial summation

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Lalit Narayan Jadhav  (10 years ago)

3+1+0.5+0.25+0.125+0.0750+0.03750+..........
=5 approximate

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bhuvaneshwaran  (7 years ago)

continuation of SOUJANYA KOLUKULURI
=> 6[1-1/n]

without knowing n value how it is get cancelled please explain

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