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(#M40020632) SELF Logical Reasoning question Keep an EYE

Four boys and three girls stand in queue for an interview. The probability that they stand in alternate positions is?

vikash singh (11 years ago)

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Read Solution (3) :

viswambher  (10 years ago)

Total number of possible arrangements for 4 boys and 3 girls in a queue = 7!
When they occupy alternate position the arrangement would be like:
B G B G B G B

Thus, total number of possible arrangements for boys = (4×3×2)
Total number of possible arrangements for girls =(3×2)

Required probability =
(4×3×2×3×2)
7!
= 1/35

Is this solution Helpfull? Yes | No (1)  

suriya  (9 years ago)

(4*3*3*2*2)=144

Is this solution Helpfull? Yes | No (1)  

Divya  (7 years ago)

Boys=4!
Girls=3!
Total for both boys and girls=4!+3!=7!
required propability=4!*3! / 7!
=4*3*2*1*3*2*1 / 7*6*5*4*3*2*1
=1/35

Is this solution Helpfull? Yes | No   

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