Latest TCS Aptitude Question SOLUTION: 55th word of SHUVANK in dictionary??

AHSNKUV
AHK----=4!
AHN----=4!
AHSK---3!
55th word is- AHSNKUV

please explain ...how v solve these type of qustn????????

Arranging the letters in alphabetical order we get : A H K N S U V
Now Total words start with A are 6!
Total words start with AH are 5! = 120
Now
Total words start with AHK are 4! = 24
Total words start with AHN are 4! = 24
Total words start with AHSK are 3! = 6
Now AHSNKUV will be the last word required.

dictionary order first take AHK---- remaining filled in=4!
next we have to take AHN----=remaining filled in=4!
AHNK---=3!
total=24+24+6=54
so next word will be
AHNKSUV
ans=AHNKSUV

A H K N S U V
firstly we need to arrange it alphabetically
now suppose we are going through an actual dictionary
we start with A ....in this dictionary the words that start from A are 6!=720
but we need 55th word which is quite smaller than 720 so forget about the words that start with H, K, N, S, U, V
so we will proceed to next character H so the words with AH are 5!=120
120 is also greater than 55.
therefore we will go for next character K so the words starting with AHK are 4!=24
now see 24 is less than 55 therefore we need to go next character for more words here we have gone through 24
words(AHKVUSN)
the thing to be noticed is all the words that have K as their 3rd character are already counted
now we need to jump to N at 3rd position i.e. AHN
therefore words with AHN are 4!=24
now 24+24(AHK+ AHN) words = 48 words...this means we have gone though all the words upto AHNVUSK
we need to get 55th
now all the words starting with AHK and AHN are counted ...we need to jump to S
therefore AHS ...words starting with AHS are 4!=24
24+24+24(AHK+AHN+AHS)=72 but we need 55th therefore we need to move back some pages/words in dictionary
now, words starting with AHS are 24 but if we need some words then we will start searching them alphabetically like first comes AHSK then AHSN then AHSU and so on
so the words beginning with AHSK are 3!=6
therfore AHK+AHN+AHSK=24+24+6=54
now we need 55th i.e. one more word
all words with AHSK are counted already now we will jump to next character of this series i.e. AHSN to AHSU ... therefore the first word that we will get using AHSN as starting characters will be the 55Th word
i.e. AHSNKUV here KUV is arranged alphabetically

dictionary order first take AHK---- remaining filled in=4!
next we have to take AHN----=remaining filled in=4!
AHNK---=3!
total=24+24+6=54
so next word will be
AHNKUSV
ans=AHNKUSV

ANHSKUV...

Arranging the letters in alphabetical order we get : A H K N S U V
Now Total words start with A are 6!
Total words start with AH are 5! = 120
Now
Total words start with AHK are 4! = 24
Total words start with AHN are 4! = 24
Total words start with AHSK are 3! = 6
Now AHSNKUV will be the last word required.

i dont know y everyone is posting copy paste answers ;)

please explain method to solve this type of question

ANHKUVS.........

can u explain with another example ........

Please anybody xplain how to solve dese kind of questions..i m helples..and why r we not using last two letters here.U,V?? Plz xplain ur answer @ankita ghosh

Arranging the letters in alphabetical order we get : A H K N S U V
Now Total words start with A are 6!
Total words start with AH are 5! = 120
Now
Total words start with AHK are 4! = 24
Total words start with AHN are 4! = 24
Total words start with AHSK are 3! = 6
Now AHSNKUV will be the last word required.

please explain me iam not able to understand

Arranging the letters in alphabetical order we get : A H K N S U V
Now Total words start with A are 6!
Total words start with AH are 5! = 120
Now
Total words start with AHK are 4! = 24
Total words start with AHN are 4! = 24
Total words start with AHSK are 3! = 6
Now AHSNKUV will be the last word required.

Why the answer could not be AHSKNUV...plz any1 explain it....!!!!

Why a proper explained solution isnt here?

AHSNKUV Words are arranged in ascending order. Thus if you take last five letters you get 5! = 120 combinations so our first ywo letters are AH . Now when you arrange last five letters in ascending order you get KNSUV .

So Place K at position 3 you get 4! = 24 combinations

then Place N at position 3 you get 4! = 24 combinations

Then Place S at position 3 and K at position 4 you get 3!= 6 combinations
Total = 54 combinations

55th AHSNKUV