Latest TCS Aptitude Question SOLUTION: Sum of three digit number is 17. sum of squared of digits of the given number is 109. If we subtract 495 from that number 5 we will get a number written in square order. find the n

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Number System

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40021593) TCS Numerical Ability question Numbers Keep an EYE

Sum of three digit number is 17. sum of squared of digits of the given number is 109. If we subtract 495 from that number 5 we will get a number written in square order. find the number.

Asked In TCS LAKSHMI (10 years ago)

Solved karthigabalamurugan Read Solution (7)

Is this Puzzle helpful?   (25)   (8) Submit Your Solution Number System

Read Solution (7) :

karthigabalamurugan  (10 years ago)

Ans:863
sum of the three digit is 17..hence a+b+c=17----(1)
sum of squared of digits is 109 ..hence a^2+b^2+c^2=109----(2)
Also, 100a+10b+c-495=100c+10b+a
99(a-c)=495
a-c=5
The possible combinations are (6,1)(7,2)(8,3),(9,4)
out of these combinations 8,3 oly satisfies both (1) nd (2)
8+b+3=17
b=6
hence 8+6+3=17
8^2+6^2+3^2=64+36+9=109
so,863 is ans...

Is this solution Helpfull? Yes (41) | No (1)  

raghavendra prasad  (8 years ago)

why 100a+10b+c-495=100c+10b+a

Is this solution Helpfull? Yes (8) | No   

pavithra  (10 years ago)

First the no which is of sum 17 of 3 digits is 386(3+8+6=17)
whose squares sum is 109 and we subtract that num by 495 we get 109 which is of sum of square order.

Is this solution Helpfull? Yes (6) | No (2)  

Akhilesh Agrawal  (10 years ago)

863

a+b+c=17
a^2+b^2+c^2=109
100a+10b+c-495=100c+10b+a
from here
a-c=5
possibilities
6-1
8-3
9-4
check it only 8 and 3 satisfy the starting two equation

Is this solution Helpfull? Yes (5) | No   

Raunak MAnchanda  (10 years ago)

Does number in square order means reverse order,i.e abc becomes cba

Is this solution Helpfull? Yes (5) | No   

Rudra  (10 years ago)

@Akhilesh Agrawal Is the sqaure order means revers order coz u changed abc to cba????

Is this solution Helpfull? Yes (2) | No   

Haritha  (7 years ago)

From the given information assume that xyz is a given number
1)x+y+z=17--------eqn(1)
2)(x^2)+(y^2)+(z^2)=109--------eqn(2)

100x+10y+z-495=100z+10y+x
100x+10y+z-495-100z-10y-x=0
99x-99z-495=0
99(x-z)=495
x-z=495/99
x-z=5
so here x value is greater than 5 and z value is less than 5
Among the possiblities of getting 5 8 and 3 satifies the equation
so x=8 and z=3
from eqn(1) y=6

so the Answer is 863

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.