Latest TCS Aptitude Question SOLUTION: Find the minimum value of abs(187m -396n + 526) where m and n are integers, if x > 0 abs(x)=x and if x < 0 then abs(x)= -x

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Find the minimum value of abs(187m -396n + 526) where m and n are integers, if x > 0 abs(x)=x and if x < 0 then abs(x)= -x

Asked In TCS dipali (11 years ago)

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Debolina Chakraborty  (11 years ago)

So to move closer to zero, 187m -396n should be closer or equal to -526
When m=1 and n=2, the value is ABS(-605+526) = 79.
when m=2 and n=3, the value is ABS(-627+526) = 101
when m=6 and n=4, the value is ABS(1122-1584+526) = 64
when m=8 and n=5, the value is ABS(1496-1980+526) = 42
when m=10 and n=6, the value is ABS(1870-2376+526) = 20
when m=12 and n=7, the value is ABS(2244-2772+526) = 2
when m=14 and n=8, the value is ABS(2618-3168+526) = 24
thus answer is 2

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Rudra  (11 years ago)

@debolina how did u choose the values of m & n I mean according to which rule???

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KAMAL HOSSAIN  (11 years ago)

m=-1,n=1
abs(-187-396+526)=abs(-57)
min =57

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hemalatha  (11 years ago)

how can u randomly choose m and n values

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