Latest AIEEE Aptitude Question SOLUTION: Prove that (sinA/cos3A) +(sin3A/cos9A) + (sin9A/cos27A) = 1/2(tan27A - tanA)

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(sinA/cos3A) +(sin3A/cos9A) + (sin9A/cos27A) = 1/2(tan27A - tanA): Asked In AIEEE MAN (11 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: If sini + cosi = 1, then the general value of i is Next Question: Add the three terms. They form a telescopic series.

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