Latest TCS Aptitude Question SOLUTION: in a tournament 8 teams have participated.in the 1st round each team will play with the other only once.top 4 will be qualified and after that knock out decision.how many total mat

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in a tournament 8 teams have participated.in the 1st round each team will play with the other only once.top 4 will be qualified and after that knock out decision.how many total matches will be played and loser will play how many match??

Asked In TCS xyz (13 years ago)

Solved virendra Read Solution (5)

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Rohit  (13 years ago)

ek team dusri team ke saath sirf ek baar hi match khel skti h.it means 1st team can play 7 matches and 2nd team can play only 6 matches and so on.....so total matches played will be 28.now 4 qualified team will play on total 3 matches to decide the winner.so total matches played are 28+3=31.
now the looser will play 7 matches + 2 matches from with that 4 qualified teams.so total wii be 9 matches.

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virendra  (13 years ago)

For 1st round no.of matches will be: 8C2 = (8*7)/2 = 28
and for semifinal and final no of matches will be= 3
so ans= 28+3=31

a looser in final will play 7+2=9 Mathes

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dhaval shah  (13 years ago)

for 1st round

no of matches played by each team=7
so total no of matches=7*8=56

for knockout round

4 teams r qualified
so total no of matches=2

for final
1 match
so total matches:56+2+1=59

now for loser
no of matches played in 1st round=7
so loser will play 7 matches

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Bunny  (13 years ago)

For Round Round 8Th Team Will Play With Remaining 7 Teams...Nxt 7Th Team Will Play Only With 6 Teams As It ALready Played With 8Th Team N One Team Plays With ANoter Only Once...In Thz Manner Total Matches Plyed Ra 7+6+5+4+3+2+1=28 iN fIRST rOUND...In Semifinals 2 Matches Final 1 Match Total 28+2+1=31 Matches

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yumnam girish  (13 years ago)

since it is knockout match then only 1 chance for each team so
2^8=256

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