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(#M40022749) BOOK question equation Keep an EYE

In an isosceles triangle ABC of area 42 cm^2, AB=AC. If the base BC=(4x+5) cm and the altitude AD = x cm the find the equal sides of the triangle, correct to two decimal places.

Asked In Book Harsh Poddar (10 years ago)

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Sachidanand Sharma  (10 years ago)

11.23cm with the base length at 21cm

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Sneha  (10 years ago)

equal sides of a triangle=11.23
let equal side of a triangle be a
area of a isosceles triangle=(b*h)/2
((4x+5)(x))/2=42
4x^2+5x-84=0
by solving the eq x=4.
so base=21 and altitude=4
altitude of a isosceles triangle(h)=sqrt(a^2-(base^2/4))
4=sqrt(a^2-(21^2/4))
by solving a=11.23

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