Latest TCS Aptitude Question SOLUTION: A circular dart board of radius 1.0 foot is at a distance of 20 feet from you. You throw a dart at it and it hits the dartboard at some point Q I th circle. What is the probability

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40002315) TCS question TCS Fresher Job Placement Paper : 14 Aug 2011 Keep an EYE

A circular dart board of radius 1.0 foot is at a distance of 20 feet from you. You throw a dart at it and it hits the dartboard at some point Q I th circle. What is the probability that Q is closer to the center of circle than the periphery?
.25
.75
.50
1.00

Solution

Since according to requirement we have to locate Q closer to center in comparison to the circumference, for doing this we shall make a circle in that board whose radius will be half of the radius of dartboard.now we will compare the area of inner circle to the total area
Answer of DIPIN is correct
area of whole circle = pi*(1 foot)^2 = pi (this is according to formula area = pi*(radius)^2
similarly area of inner circle = pi*(1/2foot)^2 = pi/4
so ratio of areas of these two circles will be the probability and that is 1/4


Like manish sir answer on facebook.

Asked In TCS Aashu (12 years ago)

Solved Read Solution (2)

Is this Puzzle helpful?   (5)   (2) Submit Your Solution

Read Solution (2) :

soumya goyal  (12 years ago)

this prblm can be solved by two methods..
1) apply area of circle formula, for Q to be closer r shud be 1/2foot.
so area of that region is pie/4. area of dartboard is pie..therefore probability is (pie/4)/pie.. =>1/4 or .25
2) second method is...we have 4 conditions..
a. dart can hit the circle.
b. dart can hit the wall.
c. dart can hit the periphery.
d. dart can hit the area closer to periphery (area b/w centre and periphery)
so for 4 situations the probability for each would be 1/4 or.25

Is this solution Helpfull? Yes (20) | No (2)  

RIJO ROY  (12 years ago)

0.50 . by taking area . upto the middle area = 0.25pi feet^2 and from middle to phriphery area = 0.75pi feet^2. so probability nearer to centre=0.25 and probability nearer to pheriphery=0.75. so difference is 0.50.

Is this solution Helpfull? Yes (1) | No (12)  

Please Login to Read Solution.