Latest TCS Aptitude Question SOLUTION: How many four digit numbers that do not contain the digit 3 or 6

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How many four digit numbers that do not contain the digit 3 or 6

Asked In TCS vignesh (10 years ago)

Solved Divya Read Solution (13)

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Read Solution (13) :

Divya  (10 years ago)

thousand place can be filled in 7 ways as it cannot start with 0 and it should nt contain 3 and 6,similarly hundreds place is filled by 8 ways(excluding 3 and 6),tens place is filled by 8 ways and unit place is filled by 8 ways.so tot=7*8*8*8=3584

Is this solution Helpfull? Yes (51) | No (2)  

chaitanya  (10 years ago)

first no in 4 digits can be filled in 7 ways(1,2,4,5,7,8,9)
next digit in 8 ways(0,1,2,4,5,7,8,9)
similarly next two digits in 8 and 8 ways
so no of ways is 7*8*8*8=3584 ways
and hence 3584 no are possible

Is this solution Helpfull? Yes (9) | No   

Himank Agrawal  (10 years ago)

7*8*8*8 = 3584

Is this solution Helpfull? Yes (3) | No   

manoj chauhan  (10 years ago)

Hiii evrybody ,there is doubt to solution of this ques;because in a ques condition is digit 3 or 6 should contain not 3 and 6 .that means if we pick up 3 then 6 should not be pick up and vica versa.
now
8*9*9*9=5832
is it right????

Is this solution Helpfull? Yes (3) | No (7)  

salman khan  (10 years ago)

7*8*8*8 = 3584

Is this solution Helpfull? Yes (2) | No   

ankush kumar agarwal  (10 years ago)

As all positions can have 10 digits each so for thousands place we cant have digits like 0,3,6 so solving according to question thousand place can be filled in 7 ways as it cannot start with 0 and it should not contain 3 and 6,similarly hundreds place is filled by 8 ways(excluding 3 and 6),tens place is filled by 8 ways and unit place is filled by 8 ways.so tot=7*8*8*8=3584

Is this solution Helpfull? Yes (1) | No   

vijay kumar singh  (10 years ago)

7*8*8*8=3584

Is this solution Helpfull? Yes (1) | No   

lucky  (10 years ago)

no should not contain 3 or 6
1st case: not having 3 so ways 8*8!
2nd case: not having 6 so ways 8*8!
3rd case: neither 3 or 5 so ways 7*7!
SO total ways 2*8*8!+7*7!

Is this solution Helpfull? Yes (1) | No (1)  

Deblina Manna  (10 years ago)

In the 4 digit no.,the first place can't be filled up by 0,3 and 6.
so we have 0-9 i.e. 10 digits-3 digits=7 digits to fill the first place
for 2nd place we can't use 3 and 6
so we can fill it by 10-2=8 possible ways
for 3rd and 4th place also,we can fill those in 8 possible ways.
so total possibility=7*8*8*8=3584

Is this solution Helpfull? Yes (1) | No   

sravani kollipara  (10 years ago)

3360
3 or 6 should not occur.
2*8*7*6*5

Is this solution Helpfull? Yes | No (8)  

Deepa  (10 years ago)

ans is 3584...
7*8*8*8=3584

Is this solution Helpfull? Yes | No   

Karthika  (10 years ago)

SO I have a doubt with this method you all have used,and y its not applicable for another question!

SO the question is the number of times 2 occurs in 1000 to 9999
I came across two methods.
Total 4 digit numbers that we can form is (9*10*10*10)
Total 4 digit numbers that we can form with out 2 is (8*9*9*9)
so 4 digit nos with 2 we can form (9*10*10*10)-(8*9*9*9) = 3168

But the general answer given by all were
Number of 2's at units place(1000 to 9999)=900
Number of 2's at tenths place(1000 to 9999)=900
Number of 2's at hundreds place(1000 to 9999)=900
Number of 2's at thousands place(1000 to 9999)=1000

therefore total number of 2's =(900+900+900+1000)=3700

Both answers are different..and please help me with is the ryt answer

Is this solution Helpfull? Yes | No   

paramesh satya  (10 years ago)

the first place do not have zero as well as 3 or 6 ..therefore 7 ways(10-3)similarly for other places zero may include ..answer is 7*8*8*8

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