Latest TCS Aptitude Question SOLUTION: Find no of ways in which 4 particular persons a,b,c,d and 6 more persons can stand in a queue so that A always stand before B. B always stand before C, And C always stand before D.

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(#M40023743) TCS Logical Reasoning question Keep an EYE

Find no of ways in which 4 particular persons a,b,c,d and 6 more persons can stand in a queue so that A always stand before B. B always stand before C, And C always stand before D.

Asked In TCS Hemanta Nandi (10 years ago)

Unsolved Read Solution (20)

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Read Solution (20) :

K.HARI  (10 years ago)

a,b,c,d are grouped ie consider them as one and remaining as 6.
total 6+1=7! ways

Is this solution Helpfull? Yes (36) | No (18)  

Shashank Shekhar  (10 years ago)

10C4*6!
first choose 4 plces out of 10 and place ABCD as mentioned which can't be arranged further(i.e they have fixed pattern) so now we have only 6 persons to arrange so 6!.

Is this solution Helpfull? Yes (24) | No (2)  

shubh mehta  (10 years ago)

it is not given that A will stand just before B so _ A _ _ B _ C _ D etc sequences can be happen.
so for this choose any 6 locations and place the 6 other persons(i.e 10C6) then at remaining 4 position A,B,C,D will arranged automatically according to the condition.so ans is 10c6*6!

Is this solution Helpfull? Yes (7) | No (2)  

Pratiksha Carpenter  (10 years ago)

Take abcd as one unit.And other 6 persons.
So we have total 7 units.
To arrange them in different ways:::No of ways=7!

Is this solution Helpfull? Yes (5) | No (3)  

saurabh   (10 years ago)

no of ways=7!*1

Is this solution Helpfull? Yes (2) | No (2)  

Akash Nigam  (10 years ago)

Ans will be 7!.
Reason: The arrangement A B C D is fixed and there are 6 more persons. Taking A B C D as one, there are 7 persons.
7 persons can stand together in 7! ways and therefore answer is 7!

Is this solution Helpfull? Yes (2) | No (2)  

gowthami kumaravadivel  (10 years ago)

(abcd)!+6! equal to 7!.ans is 7!

Is this solution Helpfull? Yes (2) | No   

Shambhu kumar  (10 years ago)

10p6 because abcd not give arrange togather

Is this solution Helpfull? Yes (2) | No (2)  

RagunathKC  (10 years ago)

ans is 10c4+7!
chances of ABCD I among 10 persons is 10c4.. and 7 person(abcd together considerd as 1) is 7!..we add it .. not mul that.
if more confuse consider ABC and just 2 more person (X,Y) solve same method.A STAND BEFORE B,B STD BF C.
ans is 5C3+3!=16.
16 possible ways are
XYABC,XAYBC,XABYC,XABCY
YXABC,YAXBC,YABXC,YABCX
AXYBC.AXBYC,AXBCY
AYXBC,AYBXC,AYBCX
ABCXY,ABCYX.

Is this solution Helpfull? Yes (2) | No (1)  

gaurav kumar  (10 years ago)

6!(for arranging 6 pepole)
7 option to place abcd taking 1 unit in between 6 person.
so ans=7*6!

Is this solution Helpfull? Yes (1) | No (7)  

ankit chauhan  (10 years ago)

7! *2 is the ans bcoz they can be arranged in 2 ways /

Is this solution Helpfull? Yes (1) | No (5)  

paramesh satya  (10 years ago)

totally ten people are there.....combinations of places are...(1234),(2345),(3456),(4567),(5678),(6789),(78910).....so 7 is the answer

Is this solution Helpfull? Yes (1) | No (2)  

muttareddy veera mani devi  (10 years ago)

(d+c+b+a)=1
remaining 6 persons can stand in 6!ways
so 1+6=7!

Is this solution Helpfull? Yes (1) | No   

Shashank Shekhar  (10 years ago)

10C4*7!
first choose 4 plces out of 10 and place ABCD as mentioned which can't be arranged further(i.e have fixed pattern) so now we have 7 peoples to arrange so 7!.

Is this solution Helpfull? Yes (1) | No   

Deepak Kumar  (9 years ago)

We have to arrange only left 6 more person.. 10p6= 10!/4!

Is this solution Helpfull? Yes (1) | No   

kurella srikanth  (10 years ago)

can u explain it

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shambhu  (8 years ago)

Manish sr what is the correct answer for this??

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TANIYA ROY  (7 years ago)

For a,b.c.d=1C1
Therefore=1C1*1C1*1C1*1C1*6!

Is this solution Helpfull? Yes | No   

SHA MD SHANAWAZ ALI  (5 years ago)

Here there are 10 persons in total. Out of which the position of 4 is always fixed(A->B->C->D). Therefore there is no chance of any other arrangements for them. Therefore we can take them as one unit. Now out of 10, after grouping the total remains 10-3units(as the 4 unit has now become only one unit, therefore the number of unit considered is only 1). Therefore it's 7 remaining,. Now as we know the number of ways in which we can arrange 7 unit is 7!, i.e on the first position,any of the seven unit, next any of remaining 6, third any of remaining 5, 4th any of remaining 4, 3rd any of remaining 3,2nd any of remaining 2 and at last the only left person. This is same as 7*6*5*4*3*2*1=7!

Is this solution Helpfull? Yes | No   

Shweta  (2 years ago)

Here the total persons are 4+6=10
So there are 10C4*6! ways=151200 ways

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