Latest IBM Aptitude Question SOLUTION: If one man do a job of two boys. If 12 men’s and 15 boys can do a work in 25 days working 7.5 hrs a day. How many boys are required along with 21 men’s to complete a work twice

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If one man do a job of two boys. If 12 men’s and 15 boys can do a work in 25 days working 7.5 hrs a day. How many boys are required along with 21 men’s to complete a work twice the first one in 50 days.

Asked In IBM aditi sharma (12 years ago)

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shashi kumar  (12 years ago)

1 man=2 boys
so,(12*2+15)boys can do a work in 25 days,working 7.5 hrs a day.
total amount of work in boy-day-hrs is (39*25*7.5)
now we have to use just this amnt of work in the question,
let x boys are required,then we get
(21*2+x)*50*7.5=2*(39*25*7.5)
x=-3 ,which is not possible.It means no boy is required .Men are already in surplus mumber.
note:always use the concept of person-day-hours in such type of problems.Believe me it's very easy and helpful.

Is this solution Helpfull? Yes (51) | No (2)  

Subhradip Biswas  (12 years ago)

12 men=24 boys
so 24+15=39 boys can do it in 25 days..
now...for 25 days job boys required=39
for 1 day job boy required=39/25
for 50 day job boy required=(39/25)*50=78
already we have 21 men=42 boys...so boys required=78-42=36 boys

Is this solution Helpfull? Yes (27) | No (23)  

Dr.Dipin Singh  (12 years ago)

If 12 men and 15 boys can do a work in 25 days working 7.5 hrs a day.
means
21 boys can do a work in 25 days working 7.5 hrs a day.
No. of boys reqd complete a work twice the first one in 50 days = 21*25*2/50 =21boys or 10.5 men .

so no additional boy is reqd as already there are surplus men.

Is this solution Helpfull? Yes (9) | No (6)  

Rajeswari  (10 years ago)

what about no.of hours working cond time

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debarati chatterjee  (7 years ago)

(21+2x)*50*7.5=2(39*25*7.5)

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