Latest TCS Aptitude Question SOLUTION: The no. of bacteria was rising exponentially. At 3pm it is 1000, at 5 pm it is 4000, then how many r there at 8 pm???

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The no. of bacteria was rising exponentially. At 3pm it is 1000, at 5 pm it is 4000, then how many r there at 8 pm???

Asked In TCS Divya Srivastava (10 years ago)

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manoj chauhan  (10 years ago)

hence its rising exponentially....
3pm-1000
4pm-2000
5pm-4000
this is series of gp
where
n=6{3,4,5,6,7,8} term
r=2000/1000=>2
a=1000
number of bacteria at 8pm=a*r^(n-1)
=1000*2^(6-1)
=1000*32
=32000 bacteria

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sugandha  (10 years ago)

4000/1000= 4
apply this formula =K*T to power 0
1000*2^2= 4000
4000*2^3=32000

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lucky  (10 years ago)

4000=1000(1+x/100)^2
so x=100%
bacteria at 8pm will be = 4000(1+100/100)^3=32000

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Durgesh Kumar Jaiswal  (10 years ago)

32000 is correct

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upendraprakash  (10 years ago)

3pm=1000
5pm=4000
2h=3000
1h=1500
3h=1500*3=4500
8pm
4000+4500=8500

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pritam kundu  (10 years ago)

as it is clear 4m d qstn dat d growth of bacteria is xponentially ,so A.P,G.P can b taken into account.
hence ((1000)^x)^x=4000
so, x=1.095
now
accordin 2 qstn the ans is=(((4000)^x)^x)^x=(4000)^(x^3)=(4000)^(1.095^3)=
53612.. x=exponential factor by which the bacteria grows per hour......

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