Latest TCS Aptitude Question SOLUTION: If A, B, C are real numbers such that (A - 2)2 + (B - 8)2 + (C - 6)2 = 0 then A + B + C is a. 0 b. 16 c. -16 d. not determinable from the information given e.

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(#M40023839) TCS question Maths Keep an EYE

If A, B, C are real numbers such that

(A - 2)2 + (B - 8)2 + (C - 6)2 = 0

then A + B + C is

a. 0

b. 16

c. -16

d. not determinable from the information given

e. 104

Asked In TCS ABHIJEET RANJAN (10 years ago)

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