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(#M40023850) TCS question Keep an EYE

Two parallel chords of circle of length 30 cm and 24 cm, radius of circle is 20 cm. Find the distance between the two chords

Asked In TCS Shyam (10 years ago)

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sreebhuvan  (10 years ago)

ANS:
SHORTEST DISTANCE= 2.77CM
LONGEST DISTANCE= 29.23CM
distance betweenONE CHORD AND CENTER=SQRT(RADIUS^2-(CHORD LENGTH/2)^2)
DISTANCE D1=SQRT((20^2)-(30/2)^2)
D1=SQRT(400-225)=SQRT(175)
D1= 13.23
DISTANCE D2=SQRT((20^2)-(24/2)^2)
D2=SQRT(400-144)=SQRT(256)
D2= 16
shortest distance between parallel chords is=D2-D1
=16-13.23
=2.77CM
LONGEST distance between parallel chords is=D2+D1
=16+13.23
=29.23CM

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sahana  (10 years ago)

use Pythagoras therom
20^2=15^2+x^2 is eql to 13.22
20^2=12^2+y^2 is eql to 16
x+y= 29.22

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prachi pawaskar  (10 years ago)

the ans will either be 29.22 or 2.78 depending upon whether the chords r on the same side or opposite side

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suresh  (10 years ago)

first consider the length of the chord 30cm say AB. the mid point of AB is m1.now draw a line from center of the circle say O to point A.now length of OA(radius)=20cm and AM=15cm(half of chord 30cm),,now using pythogras theorem we can find the distance between center of circle O to M OM distance is 13.28cm..
likewise consider 2nd chore as CD=20cm middle point as M2..for same radius draw line from O to C..OC is radius..now u know CM2=12cm OC=20cm the we can find OM2 as 16cm
for total distance add OM+OM1=113.288+16=29.228cm

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Bhavana Desa Sri Madhuri  (10 years ago)

AS R=20CM.,FOR A COMPLETE CIRCLE 2R=40 CM.,SO THAT THE DISTANCE CHORDS WILL BE 40 CM

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