Latest TCS Aptitude Question SOLUTION: find remainder 4^5^6^7+1/10

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(#M40023911) TCS question Keep an EYE

find remainder 4^5^6^7+1/10

Asked In TCS Akhilesh Agrawal (10 years ago)

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GOURAV GOURAV  (10 years ago)

the question becones 4^210+1/10.
now 1/10 always gives 1 as remainder. keep it separate.
now 4^210=16^105 =(10 +6)^105 when divided by 10 given remainder as 6^105 whose last digit is always 6. so atlast remainder would be 6. and 1 we have before.thus answer is 7.

Is this solution Helpfull? Yes (25) | No (7)  

Ankita Agasti  (10 years ago)

5
4^5^anythning means 4^odd ie remainder 4. so 4+1= 5(Ans)

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kanuru sree satya  (10 years ago)

for every number the cycle of 4 will be always repeating
Eg: 2^1=2 3^1=3 4^1=4 5^1=5
2^2=4 3^2=9 4^2=6 5^2=0
2^3=8 3^3=7 4^3=4 5^3=5
2^4=6 3^4=1 4^4=6 5^4=0 .....................
so we can easily answer when divided by 10
the given data is (4^210)+1/10
now 210 can be written as 4*52+2
therefore 52 times the cycle repeats so we need not calculate,
+2 gives the value of 4^2=6
now 6+1/10=7/10=7
so,7 is the answer
(same funda will be used to find the unit's place)

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Animesh  (10 years ago)

ans will be 1

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Durgesh Kumar Jaiswal  (10 years ago)

answer is 7.
(4^210+1)/10 remainder is 7.

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nikhil pande  (10 years ago)

ans is 7
4^5=4
4^6=6
6^7=6
6+1/10
7

Is this solution Helpfull? Yes (4) | No (1)  

mehak jindal  (10 years ago)

7 ans
4^5^6^7/10=6
1/10=1
ans 7

Is this solution Helpfull? Yes (2) | No (2)  

Bholanath   (10 years ago)

7

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mogalluri sri lakshmi kavya  (10 years ago)

your solution is very clear @kanuru sreesatya

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sandhya  (10 years ago)

i think he didnt gave ad 4^(5*6*7) but as 4^5^6^7 @gaurav@kanuru @durgesh
pls xpln clearly...

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shashi goswami  (10 years ago)

4^any odd no. =4 in unit digit*10=40, 40+1/10, so remainder is 1

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