Latest TCS Aptitude Question SOLUTION: there are 30 cans out of which only 1 is poisoned. if a person tastes very little, he will die within 14 hours. if there are mice to test and 24 hours, how many mice are required t

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(#M40002410) TCS Logical Reasoning question Keep an EYE

there are 30 cans out of which only 1 is poisoned. if a person tastes very little, he will die within 14 hours. if there are mice to test and 24 hours, how many mice are required to find the poisoned can?

Solution

If mouse would die exactly after 14 hrs then definitely 1 will be the answer but here the given condition says that mouse will die within 14 hrs.
so this question will be solved by set theory.
answer is following
total beer bottles = 6
drinking strategy
bottle1 : mouse1
bottle2 : mouse2
bottle3 : mouse3
bottle4 : mouse1 and mouse2
bottle5 : mouse2 and mouse3
bottle6 : mouse3 and mouse1
on the basis of death of mice set we can decide the poisoned bottle

in this question upto 2 bottle answer will be 1 because 2^1 = 2
similarly upto 4 bottles answer will be 2 because 2^2 = 4
for upto 8,16,32,64,128 bottles answer will be 3,4,5,6,7

For 30 can answer would be 5

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Asked In TCS satyajit kumar singh (12 years ago)

Solved Read Solution (9)

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Read Solution (9) :

Arpit Agarwal  (12 years ago)

the language here is tricky...

it`s written within 14hrs not at exactly 14th hrs so no of mice req. would be 29

if first 29 dnt die then last bottle will have the poison....

but please tell me what will be right to mark the answer in TCS apti???

Is this solution Helpfull? Yes (4) | No   

kesav telaprolu  (12 years ago)

one mice is required
for 30 cans take 30 time intervals(0.0,0.5,1,1.5,.....)
i.e after tasting the 30 cans the mice will died note the time
and subtract intervals from that time(mice died time) exactly we get 14 hours
on one particular can i.e poison can

Is this solution Helpfull? Yes (2) | No (2)  

preethi poosa  (12 years ago)

2^5=32(app. near to 30)
2^0,2^1,2^2,2^3,2^4......=> 5 mice are required to to find poisoned can...

Is this solution Helpfull? Yes (1) | No (3)  

meghanagayathri  (12 years ago)

1 mice & 14hrs 28mins are enough to get the result...
At 1st min the mice tastes 1st can & dies at 14hr
At 2nd min the mice tastes 2nd can & dies at 14hr.1Min
At 3rd min the mice tastes 3rd can & dies at 14hr.2Min
.
.
.At 29th min the mice tastes 29th can & dies at 14hr.28Min
If the mice is till alive after 14hr.28Min then the poison will be in the 30th Can....
So no death and result achieved in the last case...

Is this solution Helpfull? Yes (1) | No (2)  

ram  (12 years ago)

30
each mice for identify the poisoned for each can
time take to identify each one is 14hrs

Is this solution Helpfull? Yes | No (4)  

TAMILSELVAN DINESH  (12 years ago)

5 mice....30 near to 2 power 5

Is this solution Helpfull? Yes | No (2)  

Debabrata Bej  (12 years ago)

In the question there is no information of dying duration for mice. there's only given "if a person tastes very little, he will die within 14 hour". I don't know how everyone has calculated without having appropriate data.

Is this solution Helpfull? Yes | No   

zwaladeep  (6 years ago)

there are 30 cans out of which only 1 is poisoned. if a person tastes very little, he will die within 14 hours. if there are mice to test and 24 hours, how many mice are required to find the poisoned can?

Is this solution Helpfull? Yes | No (1)  

zwaladeep  (6 years ago)

Assign binary codes to 30 cans. you need 5 bits to represent all 30. Pick 5 mice to represent each bit. Have a mice taste all the cans for which the corresponding bit is one. After 14 hours, some will die and some wont. Set 1 for the former and 0 for the latter. The corresponding bit representation is the poisoned can.

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