Latest self Aptitude Question SOLUTION: What is the sum of 2320th term of the series 1,2,3,4,1,1,2,2,3,3,4,4,.........??

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(#M40024372) SELF question Keep an EYE

What is the sum of 2320th term of the series 1,2,3,4,1,1,2,2,3,3,4,4,.........??

Divya Srivastava (10 years ago)

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Nirmalram  (10 years ago)

sum of 1st 4 terms=10
sum of 2nd 8 terms=20
sum of 3rd 12 terms=30
so,last term can be written as 2320/4=580

sum of 580th term=n/2(2a+(n-1)d)
=580/2(2(10)+(579*10))
=290*5810
=1684900 answer

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amit kumar  (10 years ago)

2320th term of the series=
1+1+.....up to 2320times+(2+2+....upto 2320times)+(3+3+....2320times)+(4+4+....2320times)
this is because in series there are in first term every digit comes 1 times and in 2nd term every digit comes 2 times and so on.
hence sum=1*2320+2*2320+3*2320+4*2320=23200

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