Latest TCS Aptitude Question SOLUTION: In how many ways can we form 6 digit number from 1,2,3,4,5,6,7 so that last and second last digit must be even.

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(#M40024514) TCS question Keep an EYE

In how many ways can we form 6 digit number from 1,2,3,4,5,6,7 so that last and second last digit must be even.

Asked In TCS Amit Kumar (10 years ago)

Unsolved Read Solution (16)

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Read Solution (16) :

ragini dubey  (10 years ago)

it is not mentioned in the question that repetition is bot allowed that's why
the answer should be "7*7*7*7*3*3"

Is this solution Helpfull? Yes (22) | No (2)  

b.s.venkatesh  (10 years ago)

3*2*5p4=720

Is this solution Helpfull? Yes (21) | No (2)  

kalyani dangeti  (10 years ago)

last 2 digits should be even(2,4,6)=3*3
1st 4 digits can be any(1,2,3,4,5,6)=7*7*7*7
ans=7^4*3^2

Is this solution Helpfull? Yes (9) | No   

Anuradha  (10 years ago)

There are 3 even numbers : 2, 4, 6.
So, fill the last place in 3 ways. 2nd last in 2 ways.

-- -- -- -- -- -- --
5* 4* 3* 2* 1* 2* 3

ans = 720 ways

Is this solution Helpfull? Yes (8) | No (2)  

Anjali Srivastava  (10 years ago)

7*7*7*7*3*3=21609

Is this solution Helpfull? Yes (5) | No (4)  

chirag jain  (10 years ago)

5*4*3*2*3c2*2 = 720

Is this solution Helpfull? Yes (3) | No (1)  

Nitin Jha  (10 years ago)

last two digits in 3*2 ways and first four digits in 5! ways since we cn only use 13 5 7 or any one even number since two of them have been used
=> 5*4*3*2* 3*2
= 720 ways

Is this solution Helpfull? Yes (3) | No (1)  

Deblina Manna  (10 years ago)

in this question,it is not mentioned whether repitition is allowed or not.so the correct answer will be=7*7*7*7*3*3

Is this solution Helpfull? Yes (3) | No   

Rohit Bohra  (10 years ago)

5*4*3*2*2*3=720

Is this solution Helpfull? Yes (2) | No (1)  

lakshmi vyshnavi  (10 years ago)

last 2 places can be filled in 3*2 ways and remaining 4 places can be filled in 5p4.Hence the sol is 5p4*3*2=720

Is this solution Helpfull? Yes (1) | No (1)  

Fighter  (10 years ago)

3c2*2!*7c4*4!=1680

Is this solution Helpfull? Yes (1) | No (2)  

Guru Pranav  (10 years ago)

7*7*7*7*3*3=21609

Is this solution Helpfull? Yes (1) | No (2)  

Harjit kaur  (10 years ago)

Total digit are 1,2,3,4,5,6,7
First place can be filled in 4! ways
2nd place can be filled in 3!way
3rd place can be filled in 2!way
4th place can be filled in 1! ways
Since last two places consist even no so
5th place filled in 3! Ways
6th places filled in 2! Ways
So total 6 digit no formed are 4!+3!+2!+1!+3!+2!=41

Is this solution Helpfull? Yes | No (5)  

garima sharma  (10 years ago)

A=2/3B _(1)
B=C _(2)
C=1/2(A+B)_(3)
A+B+C=3000_(4)
from (2) & (4) we get:
2C+C=3000
i.e.,3C=3000
or C=1000

Is this solution Helpfull? Yes | No   

shivam shivhare  (10 years ago)

Ragini It should be 7*7*7*7*3*2.... as only three no in two different places it is asking....
if i am wrong then correct me please...

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sujan  (3 years ago)

Number of even number - 3
last 2 digit must be even so 3P2 = 6
and remaining 4 position can be arranged in 5 numbers 5P4 = 120
120*6 = 720

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