Latest TCS Aptitude Question SOLUTION: In a circle with centre O, AB and CD are two chords such that AB > CD and AB is perpendicular bisector of CD at E. P is a point on CD and when BP is extended it meets the circle at

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(#M40024643) TCS question Keep an EYE

In a circle with centre O, AB and CD are two chords such that AB > CD and AB is perpendicular bisector of CD at E. P is a point on CD and when BP is extended it meets the circle at Q. For any point P, the triangle BPE is similar to triangle
option
a) AEC
b) QDP
c) QAB
d) ABC

Asked In TCS utkarsh bisht (10 years ago)

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