Latest TCS Aptitude Question SOLUTION: in how many ways can 2310 be expressed as a product of three factors

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in how many ways can 2310 be expressed as a product of three factors

Asked In TCS karthika (10 years ago)

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Arindam Dhara  (10 years ago)

2130=2*5*7*11*3*1
6 prime factors...to express this as a product of 3 we take, (n-1)c(r-1)
5c2=10

Is this solution Helpfull? Yes (16) | No (15)  

RAA  (10 years ago)

ans is (41)

Is this solution Helpfull? Yes (6) | No (1)  

Aman Gupta  (10 years ago)

2310 = 2*3*5*7*11
We have to form a group of 3 out of these 5, it can be done in
5C2*3C2+5C3 ways i.e. 40 ways

Is this solution Helpfull? Yes (4) | No (9)  

Rohit Bohra  (10 years ago)

three is right answer??

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Asit Shukla  (10 years ago)

Is The ans 60

Is this solution Helpfull? Yes (1) | No (4)  

Ashish Aggarwal  (8 years ago)

2130 has 5 factor that are = 2,5,3,711;
so ways of making product of three factors= 5c3=5c2=10

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Guru Pranav  (10 years ago)

in 375 ways !!!

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Rahul shaw  (8 years ago)

2310 = 2*3*11*5*7
therefore, x1+x2+x3+x4+x5 = 5
(5+3-1)C(3-1) = 21

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sireesha.yammanuru  (8 years ago)

answer : 81.
2130 = 2*5*7*11*3
to experess this as a product of 3 factors let it be abc
2(only 1 digit & it it is to be counted 2 didits if it is 2^2) distributed to these 3 digits in [(1+3)C(3-1)]=3C2 ways = 3 ways
similary for 5,7,11,3 for each factor there will be 3 ways
hence total number of ways = 3*3*3*3*3= 243 ways.
Ans : 243 ways

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