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(#M40024896) TCS question remainder Keep an EYE

what is the last two digit of (123)123!

Asked In TCS gaurav (11 years ago)

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The"XESXER"  (11 years ago)

Answer is 00 because there is also present 5! and 2! this will give 00 so ans is 00.

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Krishna Chaitanya Boyanapalli  (11 years ago)

123! will have more than 2 zeroes in the end hence it will be divisible by 4 .. so we can write is as (((23)^4)^k) .. where k = 123!/4.. now since 123 ! has more than 24 zeroes at the end 123!/4 will have last two digits as zeroes.. now 23^4 = 279841 we take 41 because only last two digits are needed... so question is converted into (41)^k = last digit will be 1 and second last will be 4*0=0 so last two digits 01

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selvakumar v  (11 years ago)

123, we have 1 * 2 * 3 * ....... * 123.. so many zero will come at last.. if u multiply with any you ll get same no of zero or extra zero's.. so the answer is 00

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seetha  (11 years ago)

123! is in the power

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Asit Shukla  (11 years ago)

123! will be having more than 2 zeros at the end and 123*..00=...00

So 00 is the answer.

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K.HARI  (11 years ago)

answer is 124!-1. but 124! has more than 2 zero's
now last two digit is (0000-01)=99

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Guru Pranav  (11 years ago)

01 will be the answer !!!

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