Latest Miscellaneous Company Exam Aptitude Question SOLUTION: A bag contains 5 red & 3 black balls and the second one 4 red and 5 black balls. One of is selected at random and a draw of two balls is made from it. What is the chances that one

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(#M40002506) MISCELLANEOUS COMPAN question simple interest Keep an EYE

A bag contains 5 red & 3 black balls and the second one 4 red and 5 black balls. One of is selected at random and a draw of two balls is made from it. What is the chances that one of them is red and the other is black?

Asked In Miscellaneous Company Exam akshay tr (12 years ago)

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priya malik  (12 years ago)

secet 1 bag from two=1/2
from 1 st bag=5c1*3c1/8c2=15/28
from 2nd bag=4c1*5c1/9c2=20/36
toatl p(s)=1/2(15/28 + 20/36)=.5456

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bhargav  (12 years ago)

if 1st bag is selected,probability of getting one red and other black is
= [(5/8)*(3/7)]+[(3/8)*(5/7)]

similarly if bag 2 is selected, probability of getting one red and other black is = [(4/9)*(5/8)]+[(5/9)*(4/8)]

probability of selecting one bag is 1/2

hence answer = (1/2)[(5/8)*(3/7)]+[(3/8)*(5/7)] + (1/2)[(4/9)*(5/8)]+[(5/9)*(4/8)]

=0.5456

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