Latest TCS Aptitude Question SOLUTION: 9 years ago andromedhas age was twice achillees age. 9 years hence,andromedha age will be 4/3 times the age of achilles.find hte andromedha present age in binary numbers? a. 1101

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9 years ago andromedhas age was twice achillees age. 9 years hence,andromedha age will be 4/3 times the age of achilles.find hte andromedha present age in binary numbers?

a. 11011
b. 11000
c. 1001
d. 1010

Asked In TCS mega (10 years ago)

Unsolved Read Solution (5)

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Read Solution (5) :

Vishwadeep Solpankhi  (10 years ago)

Let andromedhas and achillees present age be x and y respectively.
now according to 1st condition
(x-9)=2*(y-9)
i.e.,x-2y=-9.....eq(1)
second condition
(x+9)=4/3(y+9)
i.e.,3x-4y=9.....eq(2)
solving eq 1 and 2 we get
x=27
On converting it into binary we get 11011==ans(a)

Is this solution Helpfull? Yes (27) | No   

sruthi  (10 years ago)

am-9 = 2(ac-9) [eq.1] am+9=4/3(ac+9) [eq2].
solving both equations . am= 27 i.e andromedha age is 27

Is this solution Helpfull? Yes (6) | No   

Arun  (10 years ago)

Let am... age =x,ach... age =y ,
9 years ago x=2y-------(1)
Present age=x+9 ,y+9
Hence 9 years thier ages x+18,y+18
x+18=(4/3)(y+18)
substituting (1)===> we get y=9
So,x's preent age=27binary value =11011

Is this solution Helpfull? Yes (3) | No   

parvez sajjad  (10 years ago)

ans is= 11011

Is this solution Helpfull? Yes | No (1)  

Sambhram P s  (4 years ago)

Let the present age of andromedha and achillees be a and b respectively.

According to first condition,

(a - 9) = 2(b-9)

=> a - 9 = 2b - 18

=> a - 2b = - 9

=> 2a - 4b = - 18 ---------(1)

According to second condition,

( a + 9) = 4 /3 ( b + 9)

=> 3a + 27 = 4b + 36

=> 3a - 4b = 9 -------(2)

On subtracting equation 1 from 2, we get

a = 9 + 18

a = 27

Now,

a - 2b = - 9

=> 27 - 2b = - 9

=> 2b = 36

=> b = 18

Andromedha's present age = 27 years

Achillees's present age = 18 years

27 in binary is 11011

Ans is option a

Is this solution Helpfull? Yes | No   

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