Latest TCS Aptitude Question SOLUTION: find sum of sharp angles in 5 pointed star

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(#M40025665) TCS Logical Reasoning question Keep an EYE

find sum of sharp angles in 5 pointed star

Asked In TCS sai venkata shiva (11 years ago)

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manoj chauhan  (11 years ago)

answer will be 180
let an angle of 5 star is a,b,c,d,e
then (180-a)+(180-b)+(180-c)+(180-d)+(180-e)=720
now a+b+c+d+e=900-720=>180

Is this solution Helpfull? Yes (15) | No (1)  

Arun  (11 years ago)

@manoj how 720 will come?

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DIVYA KUKRETI  (11 years ago)

ANS IS 180
SUM OF INTERIOR ANGLES = (NUMBER OF SIDES - 2) * 180°

For a 5-sided polygon (pentagon) this is (5-2)*180° = 3*180°=540°

Since all 5 angles of a regular pentagon are equal, each
interior angle of the regular pentagon is 540%5° = 108°
Its suppplement is found by subtracting 180°-108°=72°(the 2 angles except the sharp pointer angle)
so. pointer angle=(180-72-72)=36
similarly for rest pointed angles
so, sum of pointed angles=5*36=180

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@Ks  (11 years ago)

360 degree

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Dipika Jha  (11 years ago)

(2n-8)*90..ans is 180

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Akash Srivastava  (11 years ago)

180 degrees
ie 36 degreee of each sharp angle

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RAVI GANGWAR  (11 years ago)

ans=36*5=180

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kaustubh ingale  (11 years ago)

ans is 360

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dinesh  (11 years ago)

answer is 5*35=180.........

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sai venkata shiva  (11 years ago)

Akash Srivastava.. explain how you got 180 and how did you calculated each 36?

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Atul  (11 years ago)

answer would be 540

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Atul  (11 years ago)

sum of angle of polygon that form in between the star is
(5-2)*180=540 that is a+b+c+d+e
and let the angle of the star are a1,a2,a3,a4,a5
so 180-a1=other two angle of tringle
and those angle are equal to 180-a and 180-b so similarly
2*180-2(a+b+c+d+e)=180-a1+180-a2+180-a3+180-a4+180-a5
1800-2*(540)=900-(a1+a2+a3+a4+a5)
540=a1+a2+a3+a4+a5

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manoj chauhan  (11 years ago)

@arun check it..... http://mathforum.org/library/drmath/view/57813.html

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