Latest TCS Aptitude Question SOLUTION: In a sequence of integers A(n)=A(n-1)when A(n) is the nth term in the sequence n is an integer and n>=3,A(1)=1,A(2)=1calculate s(1000) where s(1000) is the sum of first 1000 terms

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In a sequence of integers A(n)=A(n-1)when A(n) is the nth term in the sequence n is an integer and n>=3,A(1)=1,A(2)=1calculate s(1000) where s(1000) is the sum of first 1000 terms ?

Asked In TCS Nitin Kumar (10 years ago)

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Triloki Shaw  (10 years ago)

ans would be 1. ques is incmplte it shld be A(n)=A(n-1)-A(n-2)
putting n=3,4,5.. we'll get A(3)=A(2)-A(1), A(4)=A(3)-A(2) and so on
S(1000)=1

Is this solution Helpfull? Yes (31) | No (9)  

RAKESH BHARDWAJ  (10 years ago)

This question form a series on putting values and also question is wrong.
it should be-- A(n)= A(n-1) - A(n-2)
A(3)= 1-1=0
a(4)= 0-1=-1
a(5)=-1-0=-1
a(6)=-1+1=0
a(7)= 0+1=1
a(8)= 1-0=1
a(9)= -1+1= 0
series of first six r=terms comes out to be-- 0,-1,-1,0,1,1= whose sum is zero.
Please note that here series formulation of six
there are 966 terms covered by pair of six, thus making sum zero upto 996
we are left with 1 term ie 997 term.
therefore sum= 0
because there are total 997 terms not 1000.

Is this solution Helpfull? Yes (7) | No (7)  

pragya singh  (10 years ago)

A(n)= A(n-1) n>=3(given)
so n=3,4,5,.......till 1000th term(1003)
A(3)=A(2)=1
A(4)=A(3)=1
A(5)=A(4)=1
.
.
.
.
A(1000)=A(999)=1
A(1001)=A(1000)=1
A(1002)=A(1001)=1
A(1003)=A(1002)=1
we have find sum of first 1000 terms which means...
1+1+1+1+1...............till 1000th term
sum=n/2[(2*a)+ (n-1)d]
= 1000/2[2*1+(999)*0]
= 1000Ans.

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dinesh  (10 years ago)

answer is 1000.....

Is this solution Helpfull? Yes (3) | No (14)  

RAVI GANGWAR  (10 years ago)

A(n)=A(n-1)
A(1)=1
a(2)=1
.
.
.
A(1000)=1
s(1000)=1
ans=1

Is this solution Helpfull? Yes (3) | No (2)  

prakher bhargava  (10 years ago)

A(3)=A(2)-A(1)=0,A(4)=A(3)-A(2)=-1,A(5)=A(4)-A(3)=-1,A(6)=A(5)-A(4)=0....IN THIS WAY..IF IF MAKE GROUP OF SIX NOS WE GET SUM =0;;;SO WHEN 1000 TAKEN...THERE IS 166 GROUP THAT MEANS TILL 996 ANS IS 0...SO 997=1,998=1,999=0,1000=-1 SUM OF 4 DIGITS i.e (997th+998TH+999th+1000th)term =(1+1+0-1=1) answer equal to (1)

Is this solution Helpfull? Yes (1) | No (1)  

Dheeraz  (10 years ago)

A(1)=1
A(2)=1
A(3)=A(3-1)=A(2)=1
A(4)=1


lly A(1000)=1

A(1)+A(2)+.....+A(1000)=1+1+1+......+1=1000

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Guru Pranav  (10 years ago)

1 is the answer !!!

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